WRITING A TRANSFORMED QUADRATIC FUNCTION WITH GIVEN TRANSFORMATIONS

The lowest point on a parabola that opens up or the highest point on a parabola that opens down is the vertex. The vertex form of a quadratic function is

f(x) = a(x − h)2 + k

where a ≠ 0 and the vertex is (h, k).

transformationofquadfun
  • If h > 0, move the curve h units right.
  • If h < 0, move the curve h units left.
  • If k > 0, move the curve h units up.
  • If k < 0, move the curve h units down.

Horizontal Stretches and Shrinks f(x) = x2 f(ax) = (ax)2

transformationofquadfunp1.png
  • horizontal stretch (away from y-axis) when 0 < a < 1
  • horizontal shrink (toward y-axis) when a > 1

Vertical Stretches and Shrinks f(x) = x2 a ⋅f(x) = ax2

transformationofquadfunp2.png
  • Vertical stretch (away from x-axis) when a > 1
  • Vertical shrink (toward x-axis) when 0 < a < 1

Reflections in the x-Axis :

f(x) = x2

Put y = -y

−f(x) = −(x2) = −x2

reflectionofquadfunp1

flips over the x-axis.

Reflections in the y-Axis :

f(x) = x2

Put x = -x

f(−x) = (−x)2 = x2

reflectionofquadfunp2.png

y = x2 is its own reflection in the y-axis.

Problem 1 :

f(x) = x2

vertical stretch by a factor of 2 and reflection in the x-axis followed by a translation 3 units down.

Solution :

Required transformations :

Vertical stretch -> Reflection -> Translation

Scale factor = 2

Reflection in x-axis

Translation 3 units down

2x2

-2x2

-2x2 - 3

So, the required transformed function is -2x2 - 3.

Problem 2 :

f(x) = x2

vertical shrink by a factor of 1/2, followed by a translation 3 units left.

Solution :

Required transformations :

Vertical shrink -> Translation

f(x) = (1/2)(x -(-3))2

f(x) = (1/2)(x +3)2

So, the required transformed function is 

f(x) = (1/2)(x +3)2

Problem 3 :

f(x) = 4x2 + 10

horizontal stretch by a factor of 2, followed by a translation 3 units up.

Solution :

Required transformations :

Horizontal stretch -> Translation

Replace x by (1/2)x

Problem 4 :

f(x) = (x - 2)2 - 8

horizontal shrink by a factor of 1/2 and translation 5 units down, followed by a reflection in the x-axis.

Solution :

Required transformations :

Horizontal shrink -> Translation

For horizontal shrink :

Replace x by 2x

f(x) = (2x - 2)2 - 8

For translation :

Replace k by k - 5

f(x) = (2x - 2)2 - 8 - 5

f(x) = (2x - 2)2 - 13

For reflection in x-axis :

Put y = -y

f(x) = (2x - 2)2 - 13

f(x) = -[(2x - 2)2 - 13]

f(x) = -(2x - 2)2 + 13

So, the required function is 

f(x) = -(2x - 2)2 + 13

Write a rule for g described by the transformations on the graph of f.

Problem 5 :

f(x) = x2

vertical stretch by a factor of 3 and a reflection in the x-axis by a translation 3 units down. 

Solution :

Required transformations :

Vertical stretch -> Reflection -> Translation

For horizontal shrink :

Replace x by 3x

f(x) = (3x)2

For reflection in x-axis :

Put y = -y

f(x) = -(3x)2

For translation :

Replace k by k - 3

f(x) = -(3x)2 - 3

So, the required function is 

f(x) = -3x2 - 3

Problem 6 :

f(x) = 4x+ 5

horizontal stretch by a factor of 2 and a translation 2 units up, followed by a reflection in the x-axis.

Solution :

Required transformations :

horizontal stretch -> Translation -> Reflection

For horizontal stretch :

Replace x by (1/2)x

For translation :

Replace k by k + 2

For reflection in x-axis :

Put y = -y

f(x) = -(x2+7)

f(x) = -x- 7

So, the required function is f(x) = -x- 7

Problem 7 :

Let the graph of g be a translation 4 units down and 3 units right followed by horizontal shrink by a factor of 1/2 of the graph of f(x) = x2

Solution :

Required transformations :

Translation -> Horizontal shrink

Original : f(x) = (x - 3)2 - 4

After transformation: f(x) = (2x - 3)2 - 4

So, the required translated function is 

f(x) = (2x - 3)2 - 4

Problem 8 :

Let the graph of g be a vertical stretch by a factor of 2 and a reflection in the x-axis, followed by a translation 3 units down of the graph of f(x) = x2. Write a rule for g and identify the vertex

Solution :

Original function :

f(x) = x2

For vertical stretch :

Replace x by 2x

f(x) = 2x2

For reflection in x-axis :

f(x) = -2x2

For translation :

Replace k by k - 3

f(x) = -2x2 - 3

Problem 9 :

f(x) = x2; vertical stretch by a factor of 4 and a reflection in the x-axis, followed by a translation 2 units up

Solution :

Vertical stretch --> Reflection --> Translation

f(x) = x2

For vertical stretch :

f(x) = 4x2

For reflection :

f(x) = -4x2

For translation :

f(x) = -4x2 + 2

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