The lowest point on a parabola that opens up or the highest point on a parabola that opens down is the vertex. The vertex form of a quadratic function is
f(x) = a(x − h)2 + k
where a ≠ 0 and the vertex is (h, k).
Horizontal Stretches and Shrinks f(x) = x2 f(ax) = (ax)2
Vertical Stretches and Shrinks f(x) = x2 a ⋅f(x) = ax2
Reflections in the x-Axis :
f(x) = x2
Put y = -y
−f(x) = −(x2) = −x2
flips over the x-axis.
Reflections in the y-Axis :
f(x) = x2
Put x = -x
f(−x) = (−x)2 = x2
y = x2 is its own reflection in the y-axis.
Problem 1 :
f(x) = x2
vertical stretch by a factor of 2 and reflection in the x-axis followed by a translation 3 units down.
Solution :
Required transformations :
Vertical stretch -> Reflection -> Translation
Scale factor = 2 Reflection in x-axis Translation 3 units down |
2x2 -2x2 |
So, the required transformed function is -2x2 - 3.
Problem 2 :
f(x) = x2
vertical shrink by a factor of 1/2, followed by a translation 3 units left.
Solution :
Required transformations :
Vertical shrink -> Translation
f(x) = (1/2)(x -(-3))2
f(x) = (1/2)(x +3)2
So, the required transformed function is
f(x) = (1/2)(x +3)2
Problem 3 :
f(x) = 4x2 + 10
horizontal stretch by a factor of 2, followed by a translation 3 units up.
Solution :
Required transformations :
Horizontal stretch -> Translation
Replace x by (1/2)x
Problem 4 :
f(x) = (x - 2)2 - 8
horizontal shrink by a factor of 1/2 and translation 5 units down, followed by a reflection in the x-axis.
Solution :
Required transformations :
Horizontal shrink -> Translation
For horizontal shrink :
Replace x by 2x
f(x) = (2x - 2)2 - 8
For translation :
Replace k by k - 5
f(x) = (2x - 2)2 - 8 - 5
f(x) = (2x - 2)2 - 13
For reflection in x-axis :
Put y = -y
f(x) = (2x - 2)2 - 13
f(x) = -[(2x - 2)2 - 13]
f(x) = -(2x - 2)2 + 13
So, the required function is
f(x) = -(2x - 2)2 + 13
Write a rule for g described by the transformations on the graph of f.
Problem 5 :
f(x) = x2
vertical stretch by a factor of 3 and a reflection in the x-axis by a translation 3 units down.
Solution :
Required transformations :
Vertical stretch -> Reflection -> Translation
For horizontal shrink :
Replace x by 3x
f(x) = (3x)2
For reflection in x-axis :
Put y = -y
f(x) = -(3x)2
For translation :
Replace k by k - 3
f(x) = -(3x)2 - 3
So, the required function is
f(x) = -3x2 - 3
Problem 6 :
f(x) = 4x2 + 5
horizontal stretch by a factor of 2 and a translation 2 units up, followed by a reflection in the x-axis.
Solution :
Required transformations :
horizontal stretch -> Translation -> Reflection
For horizontal stretch :
Replace x by (1/2)x
For translation :
Replace k by k + 2
For reflection in x-axis :
Put y = -y
f(x) = -(x2+7)
f(x) = -x2 - 7
So, the required function is f(x) = -x2 - 7
Problem 7 :
Let the graph of g be a translation 4 units down and 3 units right followed by horizontal shrink by a factor of 1/2 of the graph of f(x) = x2
Solution :
Required transformations :
Translation -> Horizontal shrink
Original : f(x) = (x - 3)2 - 4
After transformation: f(x) = (2x - 3)2 - 4
So, the required translated function is
f(x) = (2x - 3)2 - 4
Problem 8 :
Let the graph of g be a vertical stretch by a factor of 2 and a reflection in the x-axis, followed by a translation 3 units down of the graph of f(x) = x2. Write a rule for g and identify the vertex
Solution :
Original function :
f(x) = x2
For vertical stretch :
Replace x by 2x
f(x) = 2x2
For reflection in x-axis :
f(x) = -2x2
For translation :
Replace k by k - 3
f(x) = -2x2 - 3
Problem 9 :
f(x) = x2; vertical stretch by a factor of 4 and a reflection in the x-axis, followed by a translation 2 units up
Solution :
Vertical stretch --> Reflection --> Translation
f(x) = x2
For vertical stretch :
f(x) = 4x2
For reflection :
f(x) = -4x2
For translation :
f(x) = -4x2 + 2
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM