Problem 1 :
The product of two consecutive positive even numbers is 48. Find the numbers.
Solution:
Let the two consecutive even numbers are x and x + 2.
x(x + 2) = 48
x2 + 2x = 48
x2 + 2x - 48 = 0
x2 + 8x - 6x - 48 = 0
x(x + 8) - 6(x + 8) = 0
(x - 6) (x + 8) = 0
x = 6 or x = -8
Therefore, negative value is not possible.
x = 6 and x + 2 = 8
So, the two consecutive even positive numbers are 6 and 8.
Find the two positive integers required, if :
Problem 2 :
The numbers are consecutive and their product is 20.
Solution :
Let two consecutive numbers be x and x + 1.
x(x + 1) = 20
x2 + x = 20
x2 + x - 20 = 0
x2 + 5x - 4x - 20 = 0
x(x + 5) - 4(x + 5) = 0
(x + 5) (x - 4) = 0
x = -5 or x = 4
Therefore negative value is not possible.
So, when x = 4,
Then x + 1 = 4 + 1 = 5
Thus, two consecutive numbers are 4, 5.
Problem 3 :
The numbers are consecutive and their product is 90.
Solution:
Let two consecutive numbers be x and x + 1.
x(x + 1) = 90
x2 + x = 90
x2 + x - 90 = 0
x2 + 10x - 9x - 90 = 0
x(x + 10) - 9(x + 10) = 0
(x + 10) (x - 9) = 0
x = -10 or x = 9
Therefore negative value is not possible.
So, when x = 9,
Then x + 1 = 9 + 1 = 10
Thus, two consecutive numbers are 9, 10.
Problem 4 :
The numbers are consecutive even numbers and their product is 120.
Solution:
Let two consecutive even numbers be x and x + 2.
x(x + 2) = 120
x2 + 2x = 120
x2 + 2x - 120 = 0
x2 + 12x - 10x - 120 = 0
x(x + 12) - 10(x + 12) = 0
(x + 12) (x - 10) = 0
x = -12 or x = 10
Therefore negative value is not possible.
So, when x = 10,
Then x + 2 = 10 + 2 = 12
So, the numbers are 10, 12.
Problem 5 :
The numbers are consecutive odd numbers and their product is 63.
Solution:
Let two consecutive odd numbers be x and x + 2.
x(x + 2) = 63
x2 + 2x = 63
x2 + 2x - 63 = 0
x2 + 9x - 7x - 63 = 0
x(x + 9) - 7(x + 9) = 0
(x + 9) (x - 7) = 0
x = -9 or x = 7
Therefore negative value is not possible.
So, when x = 7,
Then 7 + 2 = 7 + 2 = 9
So, the numbers are 7, 9.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
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