USING VECTORS PROVE COMPOUND ANGLE FORMULAS

Problem 1 :

Using vector method, prove that

cos (α - β) = cos α cos β + sin α sin β

Solution :

cos-alpha-minus-beta.png

In the unit circle with center O, OA and OB are radii.

∠AOX = α, ∠BOX = β and ∠AOB = α - β

AL and AM are perpendiculars to the x-axis.

In triangle OAL,

OA = hypotenuse = 1, AL = opposite side, OL = adjacent side

A(x-coordinate, y-coordinate)

cos α = Adjacent side / hypotenuse

cos-alpha-minus-betap1.png

x-coordinate :

cos α = OL / OA

cos α = OL / 1

OL = cos α

y-coordinate :

sin α = AL / OA

sin α = AL / 1

AL = sin α

A(x-coordinate, y-coordinate)

This is how, A(cos α, sin α)

In triangle OBM,

OB = hypotenuse = 1, BM = opposite side, OM = adjacent side

B(x-coordinate, y-coordinate)

cos β = Adjacent side / hypotenuse

sin β = Opposite side / hypotenuse

x-coordinate :

cos β = OM / OB

cos β = OM / 1

OM = cos β

y-coordinate :

sin β = BM / OB

sin β = BM / 1

BM = sin β

B(x-coordinate, y-coordinate)

This is how, B(cos β, sin β)

Problem 2 :

Prove by vector method that

sin (α + β) = sin α cos β + cos α sin β

Solution :

sin-alpha-plus-beta.png

In the unit circle with center O, OA and OB are radii.

∠AOX = α, ∠BOX = β and ∠AOB = α + β

AL and AM are perpendiculars to the x-axis.

In triangle OAL,

OA = hypotenuse = 1, AL = opposite side, OL = adjacent side

A(x-coordinate, y-coordinate)

cos α = Adjacent side / hypotenuse

x-coordinate :

cos α = OL / OA

cos α = OL / 1

OL = cos α

y-coordinate :

sin α = AL / OA

sin α = AL / 1

AL = sin α

A(x-coordinate, y-coordinate)

This is how, A(cos α, sin α)

In triangle OBM,

OB = hypotenuse = 1, BM = opposite side, OM = adjacent side

B(x-coordinate, y-coordinate)

cos β = Adjacent side / hypotenuse

sin β = Opposite side / hypotenuse

x-coordinate :

cos β = OM / OB

cos β = OM / 1

OM = cos β

y-coordinate :

sin β = BM / OB

sin β = BM / 1

BM = sin β

B(x-coordinate, -y-coordinate)

This is how, B(cos β, -sin β)

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