A quadratic function is a function that can be written in the form
f(x) = a(x − h)2 + k
where a ≠ 0.
The U-shaped graph of a quadratic function is called a parabola.
f(x) = a(x − h)2 + k
Horizontal translation :
Moving the graph towards left or right.
h > 0, then move the graph right.
h < 0, then move the graph left.
Vertical translation :
Moving the graph towards up or down.
k > 0, then move the graph up.
k < 0, then move the graph down.
Reflection across x-axis :
f(x) = x2
-f(x) = -x2
Reflection across y-axis :
f(x) = x2
f(-x) = (-x)2
Horizontal stretches and shrinks :
f(x) = x2
f(ax) = (ax)2
If a > 1 (horizontal shrink)
If 0 < a < 1 (horizontal stretch)
Vertical stretches and shrinks :
f(x) = x2
a f(x) = ax2
If a > 1 (vertical stretch)
If 0 < a < 1 (vertical shrink)
Write the equation for the function y = x2 with the following transformations and draw the graph of it.
Problem 1 :
Reflect across the x-axis, shift down 1
Solution :
Transformations Reflection across x-axis Shifting down |
Transformed equations y = -x2 y = -x2 - 1 |
Problem 2 :
Vertically stretch by a factor of 3, shift right 5 and up 1
Solution :
Transformations Parent function Vertical stretch Shifting right Moving up |
Transformed equations y = x2 y = 3x2 y = 3(x - 5)2 y = 3(x - 5)2 + 1 |
Problem 3 :
If you wanted to shift
y = -3(x – 2)2 + 1
down 4 and left 5 what would be the new equation?
Solution :
Transformations Parent function Shifting down 4 units Shifting left 5 units After simplification |
Transformed equations y = -3(x – 2)2 + 1 y = -3(x – 2)2 + 1 - 4 y = -3(x - (2 - 5))2 + 1 - 4 y = -3(x + 3)2 - 3 |
So, the required quadratic function is
y = -3(x + 3)2 - 3
Problem 4 :
If you wanted to shift y = x2 + 3 left 2 and up 5 what would be the new equation?
Solution :
Transformations Parent function Shifting left 2 units Shifting up 5 units After simplification |
Transformed equations y = x2 + 3 y = (x – (-2))2 + 3 y = (x + 2)2 + 3 + 5 y = (x + 2)2 + 8 |
So, the required quadratic function is
y = (x + 2)2 + 8
Problem 5 :
If you wanted to shift y = (x + 4)2 down 3 and right 2 what would be the new equation?
Solution :
Transformations Parent function Shifting down 3 units Shifting right 2 units After simplification |
Transformed equations y = (x + 4)2 y = (x + 4)2 - 3 y = (x - (-4 + 2))2 + 3 y = (x + 2)2 + 3 |
So, the equation of the required quadratic function is
y = (x + 2)2 + 3
Problem 6 :
If you wanted to shift y = -x2 right 3 and up 5 what would be the new equation?
Solution :
Transformations Parent function Shifting right 3 units Shifting up 5 units |
Transformed equations y = -x2 y = (x - 3)2 y = (x - 3)2 + 5 |
So, the required equation is
y = (x - 3)2 + 5
Problem 7 :
Describe the following transformations on the function y = x2
y = (x + 3)2 -1
Solution :
y = (x + 3)2 -1
y = (x - (-3))2 -1
Horizontal shift of 3 units left and vertical shift of 1 unit down.
Problem 8 :
Describe the following transformations on the function y = x2
y = -(1/2)(x - 1)2 + 3
Solution :
y = -(1/2)(x - 1)2 + 3
Comparing with y = a(x - h)2 + k
a = -1/2, h = 1 and k = 3
Reflection across x -axis, vertical compression of 1/2 units, horizontal shift of 1 unit right and vertical shift of 3 units up.
Problem 9 :
Describe the following transformations on the function y = x2
y = (1/3)(x + 2)2 + 3
Solution :
y = (1/3)(x + 2)2 + 3
y = (1/3)(x - (-2))2 + 3
Comparing with y = a(x - h)2 + k
a = 1/3, h = -2 and k = 3
Vertical compression of 1/3 units, horizontal shift of 2 units left and vertical shift of 3 units up.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM