USING TRANSFORMATIONS TO GRAPH QUADRATIC FUNCTIONS

A quadratic function is a function that can be written in the form

f(x) = a(x − h)2 + k

where a ≠ 0.

The U-shaped graph of a quadratic function is called a parabola.

Translation

f(x) = a(x − h)2 + k

Horizontal translation :

Moving the graph towards left or right.

h > 0, then move the graph right.

h < 0, then move the graph left.

Vertical translation :

Moving the graph towards up or down.

k > 0, then move the graph up.

k < 0, then move the graph down.

translation-of-quadratic-function

Reflection

Reflection across x-axis :

f(x) = x2

-f(x) = -x2

Reflection across y-axis :

f(x) = x2

f(-x) = (-x)2

reflection-of-quadratic-function

Shrinks and Stretches

Horizontal stretches and shrinks :

f(x) = x2

f(ax) = (ax)2

If a > 1 (horizontal shrink)

If 0 < a < 1 (horizontal stretch)

Vertical stretches and shrinks :

f(x) = x2

a f(x) = ax2

If a > 1 (vertical stretch)

If 0 < a < 1 (vertical shrink)

stretches-and-shrinks-of-quad-fun

Write the equation for the function y = x2 with the following transformations and draw the graph of it.

Problem 1 :

Reflect across the x-axis, shift down 1 

Solution :

Transformations

Reflection across x-axis

Shifting down

Transformed equations

y = -x2

y = -x2 - 1

using-transformation-to-graph-quad-funq1

Problem 2 :

Vertically stretch by a factor of 3, shift right 5 and up 1

Solution :

Transformations

Parent function

Vertical stretch

Shifting right

Moving up

Transformed equations

y = x2

y = 3x2

y = 3(x - 5)2

y = 3(x - 5)2 + 1

using-transformation-to-graph-quad-funq2.png

Problem 3 :

If you wanted to shift

y = -3(x – 2)2 + 1

down 4 and left 5 what would be the new equation?

Solution :

Transformations

Parent function

Shifting down 4 units

Shifting left 5 units

After simplification

Transformed equations

y = -3(x – 2)2 + 1

y = -3(x – 2)2 + 1 - 4

y = -3(x - (2 - 5))+ 1 - 4

y = -3(x + 3)- 3

So, the required quadratic function is

y = -3(x + 3)- 3

Problem 4 :

If you wanted to shift y = x2 + 3 left 2 and up 5 what would be the new equation?

Solution :

Transformations

Parent function

Shifting left 2 units

Shifting up 5 units

After simplification

Transformed equations

y = x2 + 3

y = (x – (-2))2 + 3

y = (x + 2)+ 3 + 5

y = (x + 2)+ 8

So, the required quadratic function is

y = (x + 2)+ 8

Problem 5 :

If you wanted to shift y = (x + 4)2 down 3 and right 2 what would be the new equation?

Solution :

Transformations

Parent function

Shifting down 3 units

Shifting right 2 units

After simplification

Transformed equations

y = (x + 4)2

y = (x + 4)2 - 3

y = (x - (-4 + 2))+ 3

y = (x + 2)+ 3

So, the equation of the required quadratic function is 

y = (x + 2)+ 3

Problem 6 :

If you wanted to shift y = -x2 right 3 and up 5 what would be the new equation?

Solution :

Transformations

Parent function

Shifting right 3 units

Shifting up 5 units

Transformed equations

y = -x2

y = (x - 3)

y = (x - 3)+ 5

So, the required equation is 

y = (x - 3)+ 5

Problem 7 :

Describe the following transformations on the function y = x2

y = (x + 3)2 -1

Solution :

y = (x + 3)2 -1

y = (x - (-3))2 -1

Horizontal shift of 3 units left and vertical shift of 1 unit down.

Problem 8 :

Describe the following transformations on the function y = x2

y = -(1/2)(x - 1)2 + 3

Solution :

y = -(1/2)(x - 1)2 + 3

Comparing with y = a(x - h)2 + k

a = -1/2, h = 1 and k = 3

Reflection across x -axis, vertical compression of 1/2 units, horizontal shift of 1 unit right and vertical shift of 3 units up.

Problem 9 :

Describe the following transformations on the function y = x2

y = (1/3)(x + 2)2 + 3

Solution :

y = (1/3)(x + 2)2 + 3

y = (1/3)(x - (-2))2 + 3

Comparing with y = a(x - h)2 + k

a = 1/3, h = -2 and k = 3

Vertical compression of 1/3 units, horizontal shift of 2 units left and vertical shift of 3 units up.

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