Problem 1 :
For what value of K the roots of equation 2x2 + 5x + k = 0 will be rational and equal.
For what value of K the roots of the given equations are equal.
Problem 2 :
x2 + 3(k + 1)x + 4k + 5 = 0
Problem 3 :
x2 + 2(k – 2)x – 8k = 0
Problem 4 :
(3k + 6)x2 + 6x + k = 0
Problem 5 :
(k + 2)x2 – 2kx + k – 1 = 0
Problem 6 :
For what value of k the equation (4–k) x2 + 2(k+2) x + 8k + 1 = 0 will be a perfect square.
(Hint : The equation will be perfect square if Disc. b2 – 4ac = 0 )
1) k = 25/8
2) So, the value of k are 1 and -11/9.
3) So, the value of k is -2.
4) So, the values of k are -3 and 1.
5) k = 2
6) So, the value of k are 0 and 3.
Problem 1 :
Find all the values of a such that
ax2 + 3x + 5 = 0
has two real roots.
Problem 2 :
Find all values of a such that ax2 + 48x + 64 = 0 has one real root (a double root)
Problem 3 :
Find all the values of a such that
ax2 + 3x - 6 = 0
has two imaginary roots.
Problem 4 :
Find all the values of such that
2x2 - 6x + c = 0
has two imaginary roots.
Problem 5 :
Find all values of c such that -4x2 + 8x + c = 0 has two real roots.
1) a < 9/20
2) a = 9
3) a < -3/8
4) a > 9/2
5) c > -4
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM