TRANSFORMATIONS OF QUADRATIC FUNCTIONS

A quadratic function is a function that can be written in the form

f(x) = a(x − h)2 + k

where a ≠ 0.

The U-shaped graph of a quadratic function is called a parabola.

Translation

f(x) = a(x − h)2 + k

Horizontal translation :

Moving the graph towards left or right.

h > 0, then move the graph right.

h < 0, then move the graph left.

Vertical translation :

Moving the graph towards up or down.

k > 0, then move the graph up.

k < 0, then move the graph down.

translation-of-quadratic-function

Reflection

Reflection across x-axis :

f(x) = x2

-f(x) = -x2

Reflection across y-axis :

f(x) = x2

f(-x) = (-x)2

reflection-of-quadratic-function

Shrinks and Stretches

Horizontal stretches and shrinks :

f(x) = x2

f(ax) = (ax)2

If a > 1 (horizontal shrink)

If 0 < a < 1 (horizontal stretch)

Vertical stretches and shrinks :

f(x) = x2

a f(x) = ax2

If a > 1 (vertical stretch)

If 0 < a < 1 (vertical shrink)

stretches-and-shrinks-of-quad-fun.png

Problem 1 :

Which function includes a translation of 3 units to the left?

(a)  f(x) = (x + 3)2 + 1             (b)  f(x) = (x - 3)2 + 1

(c)  f(x) = 3x2 + 1                    (d)  f(x) = (x + 1)2 - 3

Solution :

Considering the quadratic function in vertex form

y = a(x - h)2 + k

Here the value of h decides the horizontal movement. Since we move the curve left 3 units, the value of h will be -3

Option a :

f(x) = (x + 3)2 + 1

f(x) = (x - (-3))2 + 1

h = -3

So, option a is correct.

Problem 2 :

Which equation shows a translation of 3 left and vertical compression by a factor of 2 to the graph of y = x2?

(a)  f(x) = 2(x - 3)2                (b)  f(x) = (1/2)(x - 3)2

(c)  f(x) = 2(x + 3)2                 (d)  f(x) = (1/2)(x + 3)2

Solution :

Translation of 3 units to the left. So, h = -3

Parent function is y = x2

Vertical compression means the curve will be observed towards y-axis.

Then, the value of a will be 0 < a < 1. Considering option d,

f(x) = (1/2)(x -(-3))2

h = -3 and a = 1/2 (0 < a < 1)

Problem 3 :

Which equation describes a parabola that opens downward, is congruent to y = x2, and has its vertex at (0, 3)?

(a)  f(x) = (x + 3)2 - 1                (b)  f(x) = -x2 + 3

(c)  f(x) = -(x - 3)2                 (d)  f(x) = x2 + 3

Solution :

Parent function :

y = x2

Vertex is at (0, 3). So, h = 0 and k = 3

Opens down, then y = -x2

f(x) = -(x - 0)2 + 3

f(x) = -x2 + 3

Problem 4 :

List the sequence of steps required to graph the function

y = -(x + 4)2 - 6

(a) horizontal translation 4 units to the right, vertical compression by a factor of 1, vertical translation 6 units down

(b) horizontal translation 4 units to the right, reflection in x-axis, vertical translation 6 units down

(c) horizontal translation 4 units to the left, vertical translation 6 units up, reflection in x-axis

(d) horizontal translation 4 units to the left, reflection in x-axis, vertical translation 6 units down

Solution :

Considering the function y = -(x + 4)2 - 6 with y = a(x - h)2 + k

Since we have negative at the beginning, it must be reflection.

a = -1 (Reflection)

h = -4 (horizontal translation to the left)

k = -6 (vertical translation down)

So, option d is correct.

Problem 5 :

Which function matches the graph?

transformation-of-quad-function-q4


(a)  f(x) = -2(x - 3)2 + 1                (b)  f(x) =  (x + 3)2 + 2 

(c)  f(x) = -2(x + 3)2 - 1             (d)  f(x) = (1/2) (x - 3)2 - 1

Solution :

By observing the curve, the vertex is at (-3, -1).

So, (h, k) ==> (-3, -1)

In option c only, we have the given vertex. So, option c is correct.

Problem 6 :

Consider a parabola P that is congruent to 

y = x2

opens upward, and has vertex (-1, 3). Now find the equation of a new parabola that results if P is reflected in the x-axis and translated 3 units down

(a)  f(x) = -(x + 4)2 + 3                (b)  f(x) =  (x - 1)2 + 6

(c)  f(x) = -(x + 1)2                (d)  f(x) = -(x - 2)2 + 3

Solution :

Parent function :

y = x2

Since (h, k) is (-1, 3)

y = (x - (-1))2 + 3

Equation of quadratic function with vertex (-1, 3) :

y = (x + 1)2 + 3

Reflected in the x-axis, so y = -(x + 1)2 + 3

Translated 3 units down, so 

y = -(x + 1)2 + 3 - 3

y = -(x + 1)2

So, the required function is y = -(x + 1)2, option c is correct.

Problem 7 :

The graphs of y = x2 and another parabola are shown below. What is a possible equation for the second parabola?

transformation-of-quad-function-q7.png

(a)  f(x) = 2x2 + 1                (b)  f(x) =  (1/2)x2 + 1

(c)  f(x) = 2(x + 1)2                (d)  f(x) = -2x2 - 1

Solution :

Comparing with the parent function, y = x2

the translated graph moved 1 unit up and there is no horizontal translation. It looks like compression towards y-axis

The scale factor should lie in between 0 to 1. Accordingly options given, option b works for the given condition.

Problem 8 :

Describe the following transformations on the function y = x2

y = -(x – 2)2

Solution :

Since h = 2 and a = -1

the graph should be reflected across y-axis and move the parent function 2 units right.

Problem 9 :

Describe the following transformations on the function y = x2

y = (1/3)(x + 2)2 + 3

Solution :

Since h = -2, k = 3 and a = 1/3 (horizontal stretch)

the graph should be moved 2 units left, 3 units down and 

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