Solve the quadratic equation by taking square roots :
Problem 1 :
5x² - 20x + 20 = 35
Solution :
5x² - 20x + 20 = 35
x² - 4x + 4 = 7
x² - 4x + 4 - 7 = 0
x² - 4x - 3 = 0
x² - 2(x)(2) - 3 = 0
x² - 2(x)(2) + 2² - 2² - 3 = 0
Using the identity (a - b)² = a² - 2ab + b²
(x - 2)² - 2² - 3 = 0
(x - 2)² - 4 - 3 = 0
(x - 2)² - 7 = 0
(x - 2)² = 7
Take square root on both sides.
√ (x - 2)² = √7
x - 2 = ±√7
x - 2 = √7 x - 2 = -√7
x = 2 + √7 x = 2 - √7
Therefore, the solutions are
x = 2 + √7 or x = 2 - √7
Problem 2 :
x² - 2/3x + 1/9 = 1
Solution :
x² - 2/3x + 1/9 = 1
x² - 2/3x - 8/9 = 0
x² - 2(x)(1/3) - 8/9 = 0
x² - 2(x)(1/3) + (1/3)² - (1/3)² - 8/9 = 0
Using the identity (a - b)² = a² - 2ab + b²
(x - 1/3)² - (1/3)² - 8/9 = 0
(x - 1/3)² - (1/9) - 8/9 = 0
(x - 1/3)² - 1 = 0
(x - 1/3)² = 1
Take square root on both sides.
√(x - 1/3)² = √1
x - 1/3 = ±1
x - 1/3 = 1 x - 1/3 = -1
x = 4/3 x = -2/3
Therefore, the solutions are
x = 4/3, x = -2/3
Problem 3 :
x² + 3/2x + 9/16 = 3
Solution :
x² + 3/2x + 9/16 = 3
x² + 3/2x + 9/16 - 3 = 0
x² + 3/2x - 39/16 = 0
x² + 2(x)(3/4) - 39/16 = 0
x² + 2(x)(3/4) + (3/4)² - (3/4)² - 39/16 = 0
Using the identity (a + b)² = a² + 2ab + b²
(x + 3/4)² - (3/4)² - 39/16 = 0
(x + 3/4)² - (9/16) - 39/16 = 0
(x + 3/4)² - 3 = 0
(x + 3/4)² = 3
Take square root on both sides.
√(x + 3/4)² = √3
x + 3/4 = ±√3
x + 3/4 = √3 x + 3/4 = -√3
x = √3 - 3/4 x = -√3 - 3/4
Therefore, the solutions are
x = ± √3 - 3/4
Problem 4 :
9x² + 12x + 4 = 5
Solution :
9x² + 12x + 4 = 5
9x² + 12x + 4 - 5 = 0
9x² + 12x - 1 = 0
x² + 4/3x - 1/9 = 0
x² + 2(x)(2/3) - 1/9 = 0
x² + 2(x)(2/3) + (2/3)² - (2/3)² - 1/9 = 0
Using the identity (a + b)² = a² + 2ab + b²
(x + 2/3)² - (2/3)² - 1/9 = 0
(x + 2/3)² - (4/9) - 1/9 = 0
(x + 2/3)² - 5/9 = 0
(x + 2/3)² = 5/9
Take square root on both sides.
√(x + 2/3)² = √5/9
x + 2/3 = ± √5/3
x = ± √5/3 - 2/3
Therefore, the solutions are
x = √5/3 - 2/3 or x = -√5/3 - 2/3
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM