SOLVING LINEAR EQUATIONS WITH RATIONAL COEFFICIENTS

To combine rational numbers, first we have to check whether the denominators are same or not.

(i) If the denominators are same, we can put one denominator and combine the numerators.

(ii) If the denominators are not same, we will take least common multiple and combine the numerators.

(iii) Keep the unknowns in one side of the equal sign.

(iv)  Do the possible simplification and get the value of unknown.

Problem 1 :

Solve:

x/2 + x/4 + x/5 + 10000 = x

Solution :

x/2 + x/4 + x/5 + 10000 = x

10000 = x/2 - x/4 - x/5

LCM of 2, 4, 5 is 20.

10000 = (20x-10x-5x-4x)/20

10000 = (20x-19x)/20

10000 = x/20

x/20 = 10000/1

Cross multiplying both sides.

x∙1 = 20∙10000

x = 200000

So, the answer is x = 200000.

Problem 2 :

If (5x/3) - 4 = 2x/5, then the numerical value of 2x-7 is

Solution :

(5x/3) - 4= 2x/5

Find common denominator

(5x - 12)/3= 2x/5

Doing cross multiplication.

5(5x-12) = 6x

25x-60 = 6x

25x-6x = 60

19x = 60

x = 60/19

The numerical value of 2x - 7= 2(60/19) - 7

= (120/19) - 7

= -13/19

Problem 3 :

-4/3y = -3/4 then y =

Solution:

Given, -4/3y = -3/4

y = (-3/4)×(-3/4)

y = (3/4)²

Hence, the value of y is (3/4)².

Problem 4 :

(x/5) + 30 = 18 has the solution as

Solution :

Transposing 30 to RHS and it becomes -30.

x/5 = 18-30

x/5 = -12

x = -12×5

x = -60

So, the solution as x = -60.

Problem 5 :

If (2/5) (x-2) = 5-(3/5)x then x = ?

Solution :

(2/5)(x-2)= 5 - (3/5)x

(2x-4) / 5 = (25-3x) / 5

Multiplying by 5 on both sides, we get

2x-4 = 25-3x

2x+3x = 25+4

5x = 29

x = 29/5

So, the answer is x = 29/5.

Problem 6 :

x/5 = (x - 1)/6

Solution :

Doing cross multiplication.

6x= 5(x-1)

6x= 5x-5

6x-5x = -5

x = -5

So, the answer is x= -5.

Problem 7:

(x/2) - (1/4) (x-1/3) = (1/6) (x+1) + (1/12)

Solution :

(x/2) - (1/4) (x-1/3) = (1/6) (x+1) + (1/12)

Combine like terms.

x/2 - x/4 + 1/12 = 1/6x + 1/6 + 1/12

LCM of 2, 4, 12 is 12 and LCM of 6, 6, 12 is 12.

(6x - 3x + 1)/12 = (2x + 2 + 1)/12

Simplify like terms.

(3x+1) / 12 = (2x+3) / 12

Multiplying by 12 on both sides, we get

3x + 1 = 2x + 3

3x - 2x = 3 - 1

x = 2

So, the answer is x = 2.

Problem 8 :

(1/2) (x + 1) + (1/3) (x - 1) = (5/12) (x - 2)

Solution :

Least common multiple of 2, 3, and 12 is 12.

[6(x + 1) + 4(x - 1)] / 12 = 5(x-2) / 12

Multiplying by 12 on both sides.

6(x + 1) + 4(x - 1) = 5(x-2)

Using distributive property.

6x + 6 + 4x - 4 = 5x - 10

10x + 2 = 5x - 10

5x = -10 - 2

x = -12/5

Recent Articles

  1. Finding Range of Values Inequality Problems

    May 21, 24 08:51 PM

    Finding Range of Values Inequality Problems

    Read More

  2. Solving Two Step Inequality Word Problems

    May 21, 24 08:51 AM

    Solving Two Step Inequality Word Problems

    Read More

  3. Exponential Function Context and Data Modeling

    May 20, 24 10:45 PM

    Exponential Function Context and Data Modeling

    Read More