What is solution in systems of linear equations ?
The point of intersection is known as solution. In general , two lines may meet at a point, they meet at infinitely many points, they will never meet.
To draw the graph of the line, we have different ways. Here we follow of finding intercepts and drawing the graph.
Find the simultaneous solution of the following pairs of equations using graphical methods:
Problem 1 :
y = 3x - 1
y = 2x - 2
Solution :
y = 3x - 1
x-intercept : y = 3x - 1 Put y = 0 3x - 1 = 0 3x = 1 x = 1/3 (1/3, 0) |
y-intercept : y = 3x - 1 Put x = 0 y = 3(0) - 1 y = -1 (0, -1) |
By connecting these two points, we get the first line.
y = 2x - 2
x-intercept : y = 2x - 2 Put y = 0 2x - 2 = 0 2x = 2 x = 1 (1/3, 0) |
y-intercept : y = 2x - 2 Put x = 0 y = 2(0) - 2 y = -2 (0, -2) |
By connecting these two points, we get the second line.
In the graph, the lines are intersecting at a point (-1, -4).
So, the solution is (-1, -4).
Problem 2 :
y = -2x + 3
y = x + 6
Solution :
y = -2x + 3
x-intercept : y = -2x + 3 Put y = 0 -2x + 3 = 0 -2x = -3 x = 3/2 (3/2, 0) |
y-intercept : y = -2x + 3 Put x = 0 y = -2(0) + 3 y = 3 (0, 3) |
By connecting these two points, we get the graph of the first line.
x-intercept : y = x + 6 Put y = 0 x + 6 = 0 x = -6 (-6, 0) |
y-intercept : y = x + 6 Put x = 0 y = 0 + 6 y = 6 (0, 6) |
So, the solution is (-1, 5).
Problem 3 :
y = -(4/3)x + 1
x = 3
Solution :
y = -(4/3) x + 1
x-intercept : y = -(4/3) x + 1 Put y = 0 -(4/3)x + 1 = 0 -(4/3)x = -1 x = 3/4 (3/4, 0) |
y-intercept : y = -(4/3) x + 1 Put x = 0 y = -(4/3)(0) + 1 y = 1 (0, 1) |
By connecting the points (3/4, 0) and (0, 1), we get the graph of the first line.
The second line is x = 3, it is vertical line passes through 3 on the x-axis.
So, (3, -3) is the solution.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
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