To simplify complex fractions, we have to be aware the concepts given below.
Simplify the fractions in the numerator and the denominator separately, then divide the two fractions and simplify.
Simplify the following :
Example 1 :
(1 + 1/x) /(1 - 1/x2)
Solution :
Simplifying numerator = (1 + 1/x) = (x + 1)/x ----(1) |
Simplifying denominator = (1 - 1/x2) = (x2-1)/x2 Using algebraic identity = (x+1) (x-1)/x2 ----(2) |
(1) / (2)
= [(x + 1)/x] / [(x + 1) (x - 1)/x2]
= [(x + 1)/x] ⋅ [x2/(x + 1) (x - 1)]
= x/(x - 1)
Example 2 :
[4 + 12/(2x - 3)] / [5 + 15/(2x - 3)]
Solution :
Simplifying the numerator :
= [4 + 12/(2x - 3)]
= [4(2x - 3) + 12] / (2x - 3)
= (8x - 12 + 12) / (2x - 3)
= 8x / (2x - 3) -------(1)
Simplifying the denominator :
= [5 + 15/(2x - 3)]
= [5(2x - 3) + 15] / (2x - 3)
= (10x - 15 + 15) / (2x - 3)
= 10x / (2x - 3) -------(2)
(1) / (2)
= 8x / (2x - 3) / 10x / (2x - 3)
= [8x / (2x - 3)] ⋅ [(2x - 3)/10x]
= 4/5
Example 3 :
[(2/x) - 5/(x + 3)] / [(3/x) + 3/(x+3)]
Solution :
Simplifying the numerator :
= [(2/x) - 5/(x + 3)]
Least common multiple of x and (x + 3) is x (x + 3)
= [2(x + 3) - 5x] / x(x + 3)
= (2x + 6 - 5x) / x(x + 3)
= (-3x + 6) / x(x + 3) ------(1)
Simplifying the denominator :
= [(3/x) + 3/(x+3)]
= [3(x + 3) + 3x] / x(x + 3)
= (3x + 9 + 3x) / x(x + 3)
= (6x + 9) / x(x + 3)
= 3(2x + 3) / x(x + 3) ------(2)
(1) / (2)
= [(-3x + 6) / x(x + 3)] / [3(2x + 3) / x(x + 3)]
= (-3x + 6) / 3(2x + 3)
= 3(2 - x) / 3(2x + 3)
= (2 - x) / (2x + 3)
Example 4 :
[x/(x + 2) - x/(x - 2)] / [x/(x + 2) + x/(x - 2)]
Solution :
Simplifying the numerator :
= [x/(x + 2) - x/(x - 2)]
Taking the least common multiple, we get
= [x(x - 2) - x(x + 2)] / (x + 2) (x - 2)
= (x2 - 2x - x2 - 2x) / (x + 2) (x - 2)
= -4x / (x + 2) (x - 2) -----(1)
Simplifying the denominator :
= [x/(x + 2) + x/(x - 2)]
= [x (x - 2) + x (x + 2)] / (x + 2) (x - 2)
= (x2 - 2x + x2 + 2x) / (x + 2) (x - 2)
= 2x2 / (x + 2) (x - 2) -----(2)
(1) / (2)
= -4x / 2x2
= -2/x
May 21, 24 08:51 PM
May 21, 24 08:51 AM
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