SEQUENCE OF TRANSFORMATIONS ON FUNCTIONS

Let us consider the function f(x), while comparing the given function with

f(x) = a f(b(x - h)) + k

it is easy to understand the concept transformation.

Here,

a = Vertical stretch or shrink

  • If a > 1, vertical stretch
  • If 0 < a < 1, vertical shrink

Note : If a is negative, there must be reflection across x-axis.

b = horizontal stretch or shrink

  • If b > 1, horizontal shrink
  • If 0 < b < 1, horizontal stretch

Note : If b is negative, there must be reflection across y-axis.

h = horizontal move

  • If h is positive, move the graph h units to the right
  • If h is negative, move the graph h units to the left.

k = vertical move

  • If k is positive, move the graph k units up.
  • If h is negative, move the graph h units down.

Problem 1 :

Describe how each transformation or sequence of transformations of the function

f(x) = 3x2

will affect the number of zeros the function has.

a) a vertical stretch of factor 2

b) a horizontal translation 3 units to the left

c) a horizontal compression of factor 2 and then a reflection in the x-axis

d) a vertical translation 3 units down

e) a horizontal translation 4 units to the right and then a vertical translation 3 units up

f) a reflection in the x-axis, then a horizontal translation 1 unit to the left, and then a vertical translation 5 units up

Solution :

f(x) = 3x2

a) a vertical stretch of factor 2

Vertical stretch = 2

f(x) = 2(3x2)

f(x) = 6x2

sequence-of-transformation-q1

b) a horizontal translation 3 units to the left

Horizontal translation = 3 units, since it is left, we should apply -3

f(x) = 3(x - h)2

Applying -3 for h, we get

f(x) = 3(x - (-3))2

= 3(x + 3)2

sequence-of-transformation-q2.png

c) a horizontal compression of factor 2 and then a reflection in the x-axis

Horizontal compression, a = 2

reflection across the x-axis, so y = -y

f(x) = 3x2

= -3(2x)2

= -3(4x2)

= -12x2

sequence-of-transformation-q3.png

d) a vertical translation 3 units down

Vertical translation, so k = -3 (since it is down 3 units)

f(x) = 3x2

f(x) = 3x2 - 3

sequence-of-transformation-q4.png

e) a horizontal translation 4 units to the right and then a vertical translation 3 units up

f(x) = 3x2

Horizontal translation = 4 (moving right)

Vertical translation = 3 (up)

f(x) = 3(x - 4)2 + 3

sequence-of-transformation-q5.png

f) a reflection in the x-axis, then a horizontal translation 1 unit to the left, and then a vertical translation 5 units up

  • Reflection across x-axis, so put y = -y
  • Horizontal translation of 1 unit to the left. So, put h = -1
  • Vertical translation of 5 units up. So, put k = 5

f(x) = 3x2

f(x) = -3(x - (-1))2 + 5

f(x) = -3(x + 1)2 + 5

sequence-of-transformation-q6.png

Problem 2 :

For the graph of f(x) = √x, identify the transformation that would not be applied to f(x) to obtain the graph y = 2f(-2x) + 3

a) Vertical stretch by a factor of 2

b) Reflection in x-axis

c) Vertical translation up 3 units.

d) Horizontal compression by factor of 1/2.

Solution :

Given function is f(x) = √x

y = 2f(-2x) + 3

By observing the transformation,

Horizontal compression of 2 units, vertical translation of 3 units up and vertical stretch of 2 units. Along with reflection across y-axis.

So, option b will not work by comparing with the list of transformations.

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