PROPERTIES OF INTERSECTING CHORDS INSIDE A CIRCLE

Find the value of x.

Problem 1:

Solution :

PK ∙ PM = PL ∙ PN

x ∙ 12 = 6 ∙ 12

12x = 72

x = 6

Problem 2 :

Solution :

BA ∙ BC = BD ∙ BE

6 ∙ 6 = x ∙ 9

36 = 9x

x = 4

Problem 3 :

Solution :

VR ∙ VT = VS ∙ VU

6 ∙ 4 = x ∙ 8

24 = 8x

x = 3

Problem 4 :

Solution :

HE ∙ HG = HF ∙ HJ

4 ∙ 10 = x ∙ 8

40 = 8x

x = 5

Problem 5 :

Solution :

GC ∙ GE = GD ∙ GF

5 ∙ 5 = 5 ∙ X

25 = 5x

x = 5

Problem 6:

Solution :

NJ ∙ NL = NK ∙ NM

x ∙ 12 = 16 ∙ 24

12x = 384

x = 32