PROBLEMS ON RATIONALIZING THE DENOMINATOR

Expressing the given fraction with out having radical terms which is at the denominator is called rationalizing denominator.

Step 1 :

Check the denominator, if consist of one term or two terms

If denominator consists of only one term :

1aTo rationalize the denominator := 1a ×aa= aa

If denominator consists of two terms :

1a+bTo rationalize the denominator := 1a+b ×a-ba-b= a-ba+ba-b

Express with integer denominator :

Problem 1 :

13 - 5

Solution :

13 - 5

Let us multiply the numerator and denominator by 3 + √5.

= 13 - 5 × 3 + 53 + 5= 3 + 5(3)2 - 52= 3 + 59 - 5= 3 + 54

Problem 2 :

12 + 3

Solution :

12 + 3

Let us multiply the numerator and denominator by 2 - √3.

= 12 + 3 × 2 - 32 - 3= 2 - 3(2)2 - 32= 2 - 34 - 3= 2 - 31= 2 - 3

Problem 3 :

14 - 11

Solution :

14 - 11

Let us multiply the numerator and denominator by 4 + √11.

= 14 - 11 × 4 + 114 + 11= 4 + 11(4)2 - 112= 4 + 1116 - 11= 4 + 115

Problem 4 :

25 + 2

Solution :

25 + 2

Let us multiply the numerator and denominator by 5 - √2.

= 25 + 2 × 5 - 25 - 2= 2 ×5 - 2(5)2 - 22= 52 - 2225 - 2= 52 - 223

Problem 5 :

33 + 3

Solution :

33 + 3

Let us multiply the numerator and denominator by 3 - √3.

= 33 + 3 × 3 - 33 - 3= 3 ×3 - 3(3)2 - 32= 33 - 329 - 3= 33 - 36= 33 - 16= 3 - 12

Problem 6 :

52 - 32

Solution :

52 - 32

Let us multiply the numerator and denominator by 2 + 3√2.

= 52 - 32 × 2 + 322 + 32= 5 ×2 + 32(2)2 - 322= 10 + 1524 - 18= 10 + 152-14

Problem 7 :

-53 + 25

Solution :

-53 + 25

Let us multiply the numerator and denominator by 3 - 2√5.

= -53 + 25 × 3 - 253 - 25= -5 ×3 - 25(3)2 - 252= -35 + 2529 - 20= -35 + 10-11

Problem 8 :

3 -72 +7

Solution :

3 -72 +7

Let us multiply the numerator and denominator by 2 - √7.

= 3 -72 +7 × 2 -72 -7= 3(2) -37 - 27 + 72(2)2 - 72= 6 -57 + 74 - 7= 13 -57-3

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