In rectangle,
Problem 1 :
PRST is a rectangle, find each angle if m∠1 = 50°
Solution :
Point 1 :
Each corner angle measures will be 90 degree.
∠TPR = ∠1+∠2 = 90
∠1 = 50, ∠2 = ?
50 + ∠2 = 90
∠2 = 90 - 50
∠2 = 40
Point 2 :
Diagonals will bisect each other and diagonals are equal.
In any triangle, sum of interior angles is 180 degree.
∠1 + ∠7 + ∠9 = 180
∠1 = ∠7 (diagonals are congruent and bisect each other).
∠1 + ∠1 + ∠9 = 180
2∠1 + ∠9 = 180
2(50) + ∠9 = 180
∠9 = 180 - 100
∠9 = 80
∠10 = 80 (vertically opposite angles)
Linear pairs are supplementary
∠9 + ∠8 = 180
80 + ∠8 = 180
∠8 = 180 - 80
∠8 = 100
∠8 = 100
∠9 = ∠10 (Vertically opposite angles)
∠2 = ∠3 = 40
∠3 + ∠4 = 90
∠4 = 50
∠7 + ∠6 = 90
50 + ∠6 = 90
∠6 = 90 - 50
∠6 = 40
∠5 = 40
∠1 = 50, ∠2 = 40, ∠3 = 40, ∠4 = 50, ∠6 = 40, ∠7 = 50, ∠8 = 100, ∠9 = 80, ∠10 = 80
PRST is a rectangle, find the value of each variable.
Problem 2 :
Solution :
In rectangle, the opposite sides will be equal.
PR = TS
7x - 4 = 6x + 4
7x - 6x = 4 + 4
x = 8
Problem 3 :
Solution :
In rectangle, each corner angles is 90 degree.
5x + 8 + 3x + 2 = 90
8x + 10 = 90
8x = 90 - 10
8x = 80
x = 80/8
x = 10
Alternate interior angles will be equal. Applying the value of x in 3x + 2, we get
= 3(10) + 2
= 30 + 2
= 32
6y + 2 = 32
6y = 32 - 2
6y = 30
y = 30/6
y = 5
So, the value of x is 10 and value of y is 5.
Problem 4 :
PS = 6x + 3, RT = 7x - 2
Solution :
Here PS and RT are diagonals. In rectangles diagonals will be equal.
PS = RT
6x + 3 = 7x - 2
6x - 7x = -2 - 3
-x = -5
x = 5
Problem 5 :
Solution :
Diagonals will bisect each other.
2x - 4 = 36
2x = 36 + 4
2x = 40
x = 40/2
x = 20
Problem 6 :
ABCD is a rectangle, with diagonals that intersect at E. Find the value of each variable
Solution :
In a rectangle, the length of diagonals will be equal.
AC = DB
2x + 6 = 36
2x = 36 - 6
2x = 30
x = 30/2
x = 15
Length of opposite sides will be equal.
2y - 6 = 12
2y = 12 + 6
2y = 18
y = 182/2
y = 9
Problem 7 :
Solution :
In any rectangle, opposite sides will be equal.
AB = DC x + 2 = 14 - 3x x + 3x = 14 - 2 4x = 12 x = 12/4 x = 3 |
AD = BC 26 = 3y + 11 3y = 26 - 11 3y = 15 y = 15/3 y = 5 |
Problem 8 :
Solution :
In any rectangle, each corner angle is 90 degree.
4x + 8 + 5x - 8 = 90
9x = 90
x = 90/9
x = 10
Problem 9 :
AC = x + 7, DB = 6x - 8
Solution :
In rectangle, length of diagonals will be equal.
AC = BD
x + 7 = 6x - 8
x - 6x = -8 - 7
-5x = -15
x = 15/5
x = 3
Problem 10 :
In the diagram below, ABCD is a rectangle with diagonals AC and BD . If the m∠2 = 58, find the measures of angles 1, 3, and 4.
Solution :
m∠2 = 58,
m∠1 + m∠2 = 90
m∠1 + 58 = 90
m∠1 = 90 - 58
m∠1 = 32
m∠1 = m∠3
m∠2 = m∠4
Problem 11 :
ABCD is a rectangle with diagonals AC and BD. If AC = 6x + 2 and DB = 12x – 10, find the value of x.
Solution :
In rectangle, length of diagonals will be equal.
AC = BD
6x + 2 = 12x - 10
6x - 12x = -10 - 2
-6x = -12
x = 12/6
x = 2
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM