Problem 1 :
D is the Midpoint of AB and E is the Midpoint of BC
If DE = 4x - 9 and AC = 3x + 22, find DE
Solution:
Using Midpoint Theorem,
2(DE) = AC
2(4x - 9) = 3x + 22
8x - 18 = 3x + 22
8x - 3x = 22 + 18
5x = 40
x = 8
Finding DE:
DE = 4x - 9
= 4(8) - 9
= 32 - 9
DE = 23
Problem 2 :
D is the Midpoint of AB and E is the Midpoint of BC
If DE = 7x + 1 and AC = 6x + 18, find AC
Solution:
Using Midpoint Theorem,
2(DE) = AC
2(7x + 1) = 6x + 18
14x + 2 = 6x + 18
14x - 6x = 18 + 2
8x = 16
x = 2
Finding AC:
AC = 6x + 18
= 6(2) + 18
= 12 + 18
AC = 30
Problem 3 :
D is the Midpoint of AB and E is the Midpoint of BC
If DE = 2x - 16 and AC = 3x - 3, find DE
Solution:
Using Midpoint Theorem,
2(DE) = AC
2(2x - 16) = 3x - 3
4x - 32 = 3x - 3
4x - 3x = 32 - 3
x = 29
To Find DE:
DE = 2x - 16
= 2(29) - 16
= 58 - 16
DE = 42
Problem 4 :
D is the Midpoint of AB and E is the Midpoint of BC
If DE = 8x - 10 and AC = 10x + 40, find AC
Solution:
Using Midpoint Theorem,
2(DE) = AC
2(8x - 10) = 10x + 40
16x - 20 = 10x + 40
16x - 10x = 40 + 20
6x = 60
x = 10
Finding AC:
AC = 10x + 40
= 10(10) + 40
= 100 + 40
AC = 140
Problem 5 :
If the perimeter of the Large Triangle is 56, find y.
Solution:
P = 4x - 7 + 6x + 4 + y
56 = 10x - 3 + y
59 = 10x - y
y = 59 - 10x ---> (1)
Using Midpoint Theorem,
2(DE) = AC
2x = 4x - 7
2x - 4x = -7
-2x = -7
x = 7/2
By applying x = 7/2 in equation (1)
y = 59 - 10(7/2)
y = 59 - 35
y = 24
Problem 6 :
If the perimeter of the Large Triangle is 30, find y.
Solution:
P = 4x - 7 + 3x + 4 + 2x + 6
30 = 9x + 3
9x = 30 - 3
9x = 27
x = 3
Using Midpoint Theorem,
2(DF) = BC
2y = 3x + 4
2y = 3(3) + 4
2y = 9 + 4
2y = 13
y = 6.5
Problem 7 :
If y = 8, find the perimeter of the Smaller Triangle.
Solution:
Perimeter of Large Triangle,
P = 4x - 15 + 2x + 2 + y
Put y = 8,
P = 4x - 15 + 2x + 2 + 8
P = 6x - 5 ---> (1)
Using Midpoint Theorem,
2(DE) = AC
2x = 4x - 15
4x - 2x = 15
2x = 15
x = 15/2
By applying x = 15/2 in (1)
P = 6(15/2) - 5
P = 45 - 5
P = 40
Perimeter of Smaller Triangle,
P = 1/2 (40)
P = 20
Problem 8 :
Find x and y.
Solution:
Using Midpoint Theorem,
2(DE) = AC 2x = 7x - 35 2x - 7x = -35 -5x = -35 x = 7 |
2(DF) = BC 2(2y) = 3x + 15 4y = 3x + 15 4y = 3(7) + 15 4y = 21 + 15 4y = 36 y = 9 |
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM