Problem 1 :
a) Given:
PQ = x2 + 3, QR = 4 + 2x, PR = 15
Find the value of x.
b) Is Q the midpoint of PR?
Solution:
PQ + QR = PR
x2 + 3 + 4 + 2x = 15
x2 + 2x + 7 = 15
x2 + 2x + 7 - 15 = 0
x2 + 2x - 8 = 0
(x + 4) (x - 2) = 0
x + 4 = 0 or x - 2 = 0
x = -4 or x = 2
So, x to be the positive value which is x = 2.
b) Is Q the midpoint of PR?
Solution:
If the distance between PQ and QR are equal, then we decide that Q is the midpoint.
PQ = x2 + 3 = 22 + 3 PQ = 7 |
QR = 4 + 2x = 4 + 2(2) QR = 8 |
Q is not the midpoint of PR.
Problem 2 :
Find the coordinate of M, the midpoint of GH, for G(8, -6), and H(-14, 12).
Solution:
Let the coordinates of M equal (x, y).
So, the coordinate of M are (-3, 3).
Problem 3 :
Find the coordinates of D if E(-6, 4) is the midpoint of DF and F has coordinates (-5, -3).
Solution:
Let the coordinates of D equal (x, y).
Find the x-coordinate -6 = (-5 + x)/2 -12 = -5 + x x = -7 |
Find the y-coordinate 4 = (-3 + y)/2 8 = -3 + y y = 11 |
So, the coordinated of D are (-7, 11).
Problem 4 :
M(-3, 2) is the midpoint of RS, and R has coordinates (6, 0). What are the coordinates of S?
Solution:
Let the coordinates of S equal (x, y).
Use the Midpoint Formula,
Equating x-coordinate : -3 = (6 + x)/2 -6 = 6 + x x = -12 |
Equating y-coordinate : 2 = (0 + y)/2 4 = 0 + y y = 4 |
So, the coordinates of S are (-12, 4).
Problem 5 :
M(7, 1) is the midpoint of WX, and X has coordinates (-1, 5). What are the coordinates of W?
Solution:
Let the coordinates of W equal (x, y).
Equating x-coordinate 7 = (-1 + x)/2 14 = -1 + x x = 15 |
Equating y-coordinate 1 = (5 + y)/2 2 = 5 + y y = -3 |
So, the coordinates of W are (15, -3).
Problem 6 :
What is the measure of ST?
Solution:
RS + ST = RT
2x + 5 + 3x + 10 = 7x + 1
5x + 15 = 7x + 1
5x - 7x + 15 - 1 = 0
-2x + 14 = 0
-2x = -14
x = 7
Measure of ST = 3x + 10
= 3(7) + 10
= 21 + 10
ST = 31
Problem 7 :
Find the coordinates of the midpoint of GH with endpoints G(-4, -7) and H(6, -15).
Solution:
Let the midpoint to be (x, y).
So, the midpoints are (1, -11).
Problem 8 :
M is the midpoint of RS and M has coordinates (-3, 1). R has coordinates (1, -4). Find the coordinates of S.
Solution:
Let the coordinates of S equal (x, y).
Use the Midpoint Formula,
Equating x-coordinate -3 = (1 + x)/2 -6 = 1 + x x = -7 |
Equating y-coordinate 1 = (-4 + y)/2 2 = -4 + y y = 6 |
So, the coordinates of S are (-7, 6).
Problem 9 :
Find the length of AM if A has coordinates (-2, 3) and B has coordinates (3, -9), and M is the midpoint of AB.
Solution:
Let the midpoint to be (x, y).
Use the Midpoint Formula,
So, the length of AM is 13/2.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM