Problem 1 :
In the equation y - y - √(4x2 + 28) = 0, x > 0 and y = 8. What is the value of x ?
A) 3 B) 4 C) 5 D) 6
Problem 2 :
√(2k2 + 17) - x = 0
If k > 0 and x = 7 in the equation above, what is the value of k ?
A) 2 B) 3 C) 4 D) 5
Problem 3 :
√(x - a) = x - 4
If a = 2, what is the solution set of the equation ?
A) {3, 6} B) {2} C) {3} D) {6}
Problem 4 :
The expression
where a and b are positive constants and x > 1, find the value of a + b.
Problem 5 :
√(k + 2) - x = 0
In the equation above k is a constant. If x = 9, what is the value of k ?
A) 1 B) 7 C) 16 D) 79
Problem 6 :
If √x + √9 = √64, find the value of x.
A) √5 B) 5 C) 25 D) 55
Problem 7 :
If √(2x + 6) + 4 = x + 3
What is the solution set of equation above ?
A) {-1} B) {5} C) {-1, 5} D) {0, -1, 5}
Problem 8 :
If k = 1, which of the following is the solution set of
x - 7 = √(x - k) ?
A) 1 B) 5 C) 10 D) 5, 10
Problem 9 :
If √49 = √y - √16, what is the value of y ?
A) 121 B) 65 C) 11 D) √11
Problem 10 :
√(c - 1) - t = 0
In the equation above, c is a constant. If t = 4, what is the value of c ?
A) 17 B) 15 C) 5 D) 3
Problem 11 :
a - 6 = √(8a - 7) - 4
What is the solution set of the equation above ?
A) 0 B) 1 C) 11 D) 1, 11
1) 3, option A is correct.
2) the value of k is 4, option C
3) x = 6 and x = 3, option A
4) 361/8
5) x = 79, option D
6) x = 25
7) x = 5 and x = -1, option C
8) x = 10 and x = 5
9) y = 121
10) c = 17
11) So, the solution are 1 and 11.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM