Mean :
The arithmetic mean of a given data is the sum of all observations divided by the number of observations.
Mean = (Sum of all observations)/Number of observations
Median :
The median is the middle value of a given data when those values are arranged from ascending to descending order.
Median = Middle value
To find the median from ungrouped data, we have to consider if n is odd or even.
If n is odd, then using the formula
Median = (n+1)th term/2
If n is even, then using the formula
Median = [(nth/2) term + (n/2+1)th term]/2
Mode :
The mode is the value that occurs most often in the given data.
Find the mean of the numbers.
Problem 1 :
2, 4, 1, 0, 1, and 1
Solution :
Given, 2, 4, 1, 0, 1, and 1
Mean = (sum of the terms)/(number of the terms)
= (2 + 4 + 1 + 0 + 1 + 1)/6
= 9/6
= 3/2
= 1.5
Hence the mean is 1.5
Problem 2 :
$270, $310.50, $243.75, and $252,15
Solution :
Given, $270, $310.50, $243.75, and $252,15
Mean = (sum of the terms)/(number of the terms)
= ($270 + $310.50 + $243.75 + $252.15)/4
= $1076.4/4
= $269.1
Hence the mean is 269.1
Problem 3 :
Each workday last week, Yoshie kept track of the number of minutes she had to wait for the bus. She waited 3, 0, 8,1 and 8 minutes. Find the mean.
Solution :
The number of minutes = 3, 0, 8, 1 and 8
Mean = (sum of the terms)/(number of the terms)
= (3 + 0 + 8 + 1 + 8)/5
= 20/5
= 4
Hence the mean is 4.
Problem 4 :
In the last three months, Raul’s water bills were $31.45, $48.76, and $42. 60. Find the mean.
Solution :
Raul’s water bills = $31.45, $48.76, and $42. 60.
Mean = (sum of the terms)/(number of the terms)
= ($31.45 + $48.76 + $42.60)/3
= $122.81/3
= $40.94
Hence the mean is $40.94.
Find the Median of a Set of Numbers.
Problem 5 :
41, 45, 32, 60, 58
Solution :
Given, 41, 45, 32, 60, 58
Arrange the data in ascending order.
= 32, 41, 45, 58, 60
n = 5
Median = ((n + 1)/2)th term
= ((5 + 1)/2)th term
= (6/2)th term
= 3 term
= 45
Hence the median is 45.
Problem 6 :
25, 23, 24, 26, 29, 19, 18, 32
Solution :
Given, 25, 23, 24, 26, 29, 19, 18, 32
Arrange the data in ascending order.
= 18, 19, 23, 24, 25, 26, 29, 32
n = 8(even)
Median = ((n/2)th term + (n/2 + 1)th term)/2
= ((8/2)th term + (8/2 + 1)th term)/2
= (4th term + 5th term)/2
= (24 + 25)/2
= 49/2
Hence the median is 24.5
Problem 7 :
The ages of the eight men in Jerry’s model train club are 52, 63, 45, 51, 55, 75, 60, and 59. Find the median age.
Solution :
Number of ages = 52, 63, 45, 51, 55, 75, 60, and 59.
Arrange the data in ascending order.
= 45, 51, 52, 55, 59, 60, 63, 75
n = 8(even)
Median = ((n/2)th term + (n/2 + 1)th term)/2
= ((8/2)th term + (8/2 + 1)th term)/2
= (4th term + 5th term)/2
= (55 + 59)/2
= 114/2
= 56
Hence the median age is 56.
Problem 8 :
The number of clients at Miranda’s beauty salon each weekday last week were 18, 7, 12, 16, and 20. Find the median number of clients.
Solution :
Number of clients = 18, 7, 12, 16, and 20.
Arrange the data in ascending order.
= 7, 12, 16, 18, 20
n = 5(odd)
Median = ((n + 1)/2)th term
= ((5 + 1)/2)th term
= (6/2)th term
= 3 term
= 16
Hence the median is 16.
Find the Mode of a Set of Numbers.
Problem 9 :
6, 4, 4, 5, 6, 6, 4, 4. 4, 3, 5
Solution :
Given, 6, 4, 4, 5, 6, 6, 4, 4. 4, 3, 5
Mode is the most repetitive value of a given set of values.
= 4, 5, 6
So, the mode is 4, 5, 6.
Problem 10 :
The number of siblings of a group of students :
2, 0, 3, 2, 4, 1, 6, 5, 4. 1, 2, 3
Solution :
Given, 2, 0, 3, 2, 4, 1, 6, 5, 4. 1, 2, 3
Mode is the most repetitive value of a given set of values.
= 1, 2, 3, 4
So, the mode is 1, 2, 3, 4.
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