PLOTTING IRRATIONAL NUMBERS ON A NUMBER LINE

To plot irrational numbers on the number line, we have to memorize some of the following values given below.

√1 = 1

√4 = 2

√9 = 3

√16 = 4

√25 = 5

√36 = 6

√49 = 7

√64 = 8

√81 = 9

√100 = 10 

For example, 

√27

The approximate value of √27 is 5....., because 

√25 < √27 <√36

So, in the number line, in between 5 and 6, we have to mark it.

What is rational number ?

All numbers that can be written in the form of p/q is rational number.

What are irrational numbers ?

The numbers that cannot be written in the form of fraction, those are irrational numbers.

For example, 

√2, √3, √5, .......etc are examples of irrational numbers.

Consider, √4, √9, √25 ....... etc

these are not irrationals, because 

√4 = √(2 x 2) ==> 2

Since we can write it as fraction, it cannot be irrational. It is rational.

Place a point on the number line given for each of the following irrational numbers.

Problem 1 :

Point A :√2

Solution :

Point A :√2

√2 lies between √1 and √3.

Approximate value of √2 is 1.414. 

So, the point 1.414 lies between 1.0 and 1.5.

Problem 2 :

Point B :√17

Solution :

Point B :√17

√17 lies between √16 and √25.

Approximate value of √17 is 4.1. 

So, the point 4.1 lies between 4 and 4.5.

Problem 3 :

Point C :√11

Solution :

Point C :√11

√11 lies between √9 and √16.

Approximate value of √11 is 3.3....  

So, the point 3.3 lies between 3.0 and 3.5.

Problem 4 :

Point D :√8

Solution :

Point D :√8

√8 lies between √2 and √9 and it is more nearer to √9.

Approximate value of √8 is 2.8

So, the point 2.8 lies between 2.5 and 3.0.

Problem 5 :

Point E :√5

Solution :

√5 lies between √2 and √9.

Approximate value of √5 is 2.24. 

So, the point 2.24 lies between 2.0 and 2.5.

Problem 6 :

Point V :√26

Solution :

Point V :√26

√26 lies between √25 and √36.

Approximate values of √26 is 5.1....

So, the point 5.1 lies between 5.0 and 5.5.

Problem 7 :

Point W :√88

Solution :

Point W : √88

√88 lies between √81 and √100.

Approximate value of √88 is 9.38. 

So, the point 9.4 lies between 9.0 and 9.5.

Problem 8 :

Point X :√77

Solution :

Point X :√77

√77 lies between √64 and √81.

Approximate value of √77 is 8.7. 

So, the point 8.7 lies between 8.5 and 9.0.

Problem 9 :

Point Y :√37

Solution :

Point Y : √37

√37 lies between √25 and √36.

Approximate value of √37 is 6.1

So, the point 6.1 lies between 6.0 and 6.5.

Problem 10 :

Point Z :√30

Solution :

Point z :√30

√30 lies between √25 and √36.

Approximate values of √30 is 5.3  

So, the point 5.3 lies between 5.0 and 5.5.

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