Always the original price should be considered as 100%.
Let x% be the percentage should be increased, then the new quantity will be (100+x)% of the old quantity.
Let x% be the percentage should be decreased, then the new quantity will be (100-x)% of the old quantity.
Example 1 :
Increase 20 by 50%
Solution :
Original quantity = 20
Should be increased by 50%.
Original quantity can be considered as 100%.
Then the new quantity = (100 + 50)% of the old quantity
= 150% of 20
= 1.50 (20)
= 30
Example 2 :
Increase 32 by 75%
Solution :
Original quantity = 32
Should be increased by 75%.
Original quantity can be considered as 100%.
Then the new quantity = (100 + 75)% of the old quantity
= 175% of 32
= 1.75 (32)
= 52.5
Example 3 :
Decrease 55 by 40%
Solution :
Original quantity = 55
Should be decreased by 40%.
Original quantity can be considered as 100%.
Then the new quantity = (100 - 40)% of the old quantity
= 60% of 55
= 0.60 (55)
= 33
Example 4 :
Decrease 6 kg by 5%
Solution :
Original quantity = 6
Should be decreased by 5%.
Original quantity can be considered as 100%.
Then the new quantity = (100 - 5)% of the old quantity
= 95% of 6
= 0.95 (6)
= 5.7
Example 5 :
Increase 670 by 1.2%
Solution :
Original quantity = 670
Should be increased by 1.2%.
Original quantity can be considered as 100%.
Then the new quantity = (100 - 1.2)% of the old quantity
= 98.8% of 6
= 0.988 (6)
= 5.928
Example 6 :
When a tennis ball is dropped, it bounces and then rises. The ball rises to 80% of the height from which it is dropped. The ball is dropped from a height of 4 meters.
(a) Calculate the height of the rise after the first bounce.
(b) Calculate the height of the rise after the second bounce.
Solution :
(a) Height of the ball when it is dropped = 4 meters
The ball rises 80% of the original height.
So, 180% of the ball's height = 1.80(4)
= 7.2 meter
Now the height of the ball is 7.2 meter.
(b) Again it will raise 80% of the original height.
So, 180% of 7.2 :
= 1.80 (7.2)
= 12.96
Example 7 :
When a number is first increased by 10% and then reduced by 10%, the number,
a) does not change b) decreases by 1% c) increases by 1%
d) none of these
Solution :
Let x be the required number. After increasing the number 10%, the new number will be
= 110% of x
Reducing 10%, then the new number will be 90% of 110% of x
= 0.90(1.10x)
= 0.99x
= (99/100) of x
So, the original number x decreases by 1%.
Example 8 :
If the side of the square is increased by 25%, then its area is increased by
a) 25% b) 55% c) 40.5% d) 56.25%
Solution :
Let x be the side length of the square. Since the side length of the square is increased by 25%, the new side length will be 125% of x
Area of square = 125% of x (125% of x)
= 1.25x (1.25x)
= 1.5625x
= (156.25/100) of x
= 156.25% of x
Increased by 56.25%. So, the answer is option d.
Example 9 :
An article listed at 5400 is offered at a discount of 15%. Due to festival season, the shopkeeper allows a further discount of 5%. Find the selling price of the article.
Solution :
Original price of the article = $5400
After announcing 15% discount, the new price = 85% of 5400
= 0.85(5400)
= 4590
Further discount of 5%, then the new price will be 95% of 4590
= 0.95(4590)
= 4360.5
So, the new selling price will be $4361
Example 10 :
A’s income is 25% more than that of B. B’s income is 8% more than that of C. If A’s income is $20250, then find the income of C.
Solution :
Let x be the income of C.
B's income = 108% of C
A's income = 125% of 108% of C
= 1.25(1.08C)
Applying A's income, we get
20250 = 1.25(1.08C)
C = 20250/(1.25)(1.08)
C = 15000
So, C's income is $15000.
Example 11 :
A reduction of 10% in the price of tea enables a dealer to purchase 25 kg more tea for $22500. What is the reduced price per kg of tea? Also, find the original price per kg.
Solution :
10% of $22500 = (10/100) × 22500
= $2250
Reduced price of 25 kg tea = $2250
2250/25
= $90 per kg
Reduced price per kg = $25
Since, the reduction was 10% so the original price = $100 per kg.
Example 12 :
60 is reduced to 45. What percent is the reduction?
Solution :
Percentage change = (old value - new value)/old value x 100%
= [(60 - 45)/60] x 100%
= (15/60) x 100%
= 25%
Example 13 :
If 80 is increased to 125, what is the increase percent?
Solution :
Percentage change = (old value - new value)/old value x 100%
= [(125 - 80)/80] x 100%
= (45/80) x 100%
= 56.25%
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM