To compare two quantities, they should be in the same kind.
Fraction with another fraction can be compared easily. Decimal with another decimal can be compared easily.
If we want to compare fraction and decimal, first let us check whether it is simple to make the fraction as decimal without performing long division.
If we have 10, 100, 1000, ....... at the denominator, we can simply change it as decimal.
Some times it will be very simple to convert fraction as decimal by making the denominator as multiple of 10's.
For example,
In the following exercises, write each set of numbers in order from least to greatest.
Problem 1 :
3/5, 9/16, 0.55
Solution :
Let us change 3/5 to a decimal.
(3/5) ∙ (20/20) = 60/100 = 0.6
Doing long division, we can convert 9/16 as decimal.
9/16 = 0.56
Compare the decimals
0.55 < 0.56 < 0.6
Substitute the corresponding original fraction
Least to greatest
0.55 < 9/16 < 3/5
To make it as multiple of 10.
4 x 25 = 100
8 x 125 = 1000
5 x 2 =10
To convert the decimal as fraction, we have to observe that the number of digits after the decimal.
In the following exercises, write each set of numbers in order from least to greatest.
Problem 2 :
3/8, 7/20, 0.36
Solution :
Doing long division, we can convert 3/8 as decimal.
3/8 = 0.375
(7/20)∙(5/5) = 35/100 ==> 0.35
Compare the decimals
0.35 < 0.36 < 0.375
Substitute the corresponding original fraction
Least to greatest
7/20 < 0.36 < 3/8
Problem 3 :
0.702, 13/20, 5/8
Solution :
Doing long division, we can convert 13/20 and 5/8 as decimal.
(13/20) ∙ (5/5) = 65/100 ==> 0.65
(5/8) ∙ (125/125) = 625/1000 ==> 0.625
Compare the decimals
0.625 < 0.65 < 0.702
Substitute the corresponding original fraction
Least to greatest
5/8 < 13/20 < 0.702
Problem 4 :
0.15, 3/16, 1/5
Solution :
Doing long division, we can convert 3/16 as decimal.
3/16 = 0.187
Let us change 1/5 to a decimal.
(1/5) ∙ (20/20) = 20/100 = 0.2
Compare the decimals
0.15 < 0.187 < 0.2
Substitute the corresponding original fraction
Least to greatest
0.15 < 3/16 < 1/5
Problem 5 :
-0.3, -1/3, -7/20
Solution :
Doing long division, we can convert -1/3as decimal.
-1/3 = -0.33
(-7/20) ∙ (5/5) = -35/100 ==> -0.35
Compare the decimals
-0.35 < -0.33 < -0.3
Substitute the corresponding original fraction
Least to greatest
-7/20 < -1/3 < -0.3
Problem 6 :
-0.2, -3/20, -1/6
Solution :
(-3/20) ∙ (5/5) = -15/100 ==> -0.15
Doing long division, we can convert -1/6 as decimal.
-1/6 = -0.16
Compare the decimals
-0.2 < -0.16 < -0.15
Substitute the corresponding original fraction
Least to greatest
-0.2 < -1/6 < -3/20
Problem 7 :
-3/4, -7/9, -0.7
Solution :
Let change -3/4 to a decimal
(-3/4) ∙ (25/25) = -75/100 = -0.75
Doing long division, we can convert -7/9 as decimal.
-7/9 = -0.778
Compare the decimals
-0.778 < -0.75 < -0.7
Substitute the corresponding original fraction
Least to greatest
-7/9 < -3/4 < -0.7
Problem 8 :
-8/9, -4/5, -0.9
Solution :
Doing long division, we can convert -8/9 as decimal.
-8/9 = -0.88
Let change -4/5 to a decimal
(-4/5) ∙ (20/20) = -80 /100 = -0.8
Compare the decimals
-0.9 < -0.88 < -0.8
Substitute the corresponding original fraction
Least to greatest
-0.9 < -8/9 < -4/5
Problem 9 :
Write these numbers in order of size. Start with the smallest number.
60%, 1/2, 0.3, 3.4, 0.4
Solution :
60% can be written by writing the denominator as 100.
60% = 60/100
To convert it into decimal, since we have two zeroes in 100, we have to move the decimal two digits to the left.
1/2 = 0.5
0.3, 3.4, 0.4
These are already decimals, so the comparision can be made simply now.
0.3, 0.4, 0.5, 0.6, 3.4
Arranging
0.3, 0.4, 1/2, 60%, 3.4
Problem 10 :
The heights of seven footballers are listed below.
1.9 m, 1.82 m, 1.78 m, 1.8 m, 1.88 m, 1.86 m, 1.7 m
(a) Arrange the heights in order from smallest to largest.
(b) Write down the median height.
(c) A player is picked at random. Write down the probability that he is over 1.85 m.
Solution :
(a) Arrange the heights in order from smallest to largest.
Given that,
1.9 m, 1.82 m, 1.78 m, 1.8 m, 1.88 m, 1.86 m, 1.7 m
Arranging from smallest to largest,
1.7, 1.78, 1.8, 1.82, 1.86, 1.88, 1.9
(b) Median height = 1.82
(c) Total number of samples = 7
Number of samples which are more than 1.85 = 3
Required probability = 3/7
Problem 11 :
Astronaut A is making some food. He needs to add 1 litres of water to the powder. Astronaut B is preparing a different meal. She needs to add 1.2 litres of water. How many more millilitres of water does astronaut A’s food need compared with astronaut B’s?
Solution :
Amount of water Astronaut A needs to add = 1 liter
Amount of water Astronaut B needs to add = 1.2 liter
Astronaut B wants to add more quantity of water, to find how much more we have to find the difference.
= 1.2 - 1
= 0.2 liters.
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May 21, 24 08:51 AM
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