Express the relation as
i) set of ordered pairs
ii) Table
iii) Graph
iv) mapping diagram
Problem 1 :
In the scoring of some track meets, for 1st place you get 5 points, for 2nd place you get 3 points, for 3rd place you get 2 points and for 4th place you get 1 point.
Problem 2 :
g(m) = m2
for the domain {-2, 0 2}
Problem 3 :
h(x) = -1/3x – 1
for the domain {-3, 0, 6}
Problem 4 :
A tanning salon charges a one – time maintenance fee of $12 plus $4 for each tanning visit. Write a function to describe the situation. Find a reasonable domain and range for the function for up to 6 visits.
Problem 5 :
f(x) = x2 + x – 2
for the domain {-2, 0 1}
1)
a) {(1, 5), (2, 3), (3, 2), (4, 1)}
b)
Place 1 2 3 4 |
Points 5 3 2 1 |
c)
d)
2) m = -2, g(-2) = 4, m = 0, g(0) = 0, m = 2, g(2) = 4
a) Set of ordered pairs is
{(-2, 4), (0, 0), (2, 4)}.
b) Table of values :
g(m) g(-2) g(0) g(2) |
m2 4 0 4 |
c) Graph
d) Mapping diagram
3) x = -3, h(-3) = 0, x = 0, h(0) = -1, x = 6, h(6) = -3
a) Set of ordered pairs is
{(-3, 0), (0, -1), (6, -3)}.
b) Table
h(x) h(-3) h(0) h(6) |
-1/3x - 1 0 -1 -3 |
c) Graph
d) Mapping diagram
4) y = 12 + 4x
0 ≤ x ≤ 6 and x should be an integer.
x = 0, y = 12, x = 1, y = 16, x = 2, y = 20
x = 3, y = 24, x = 4, y = 28, x = 5, y = 32
x = 6, y = 36
domain = {0, 1, 2, 3, 4, 5, 6}.
Range = {12, 16, 20, 24, 28, 32, 36}
a. Set of ordered pairs :
{(0, 12), (1, 16), (2, 20), (3, 24), (4, 28), (5, 32), (6, 36)}.
b) Table :
x 0 1 2 3 4 5 6 |
y 12 16 20 24 28 32 36 |
c) Graph :
d) Mapping Diagram :
5) x = -2, f(-2) = 0, x = 0, f(0) = -2, x = 1, f(1) = 0
range = {-2, 0}
a. Set of ordered pairs :
{(-2, 0), (0, -2), (1, 0)}.
b. Table :
f(x) f(-2) f(0) f(1) |
x2 + x - 2 0 -2 0 |
c. Graph :
d. Mapping Diagram :
Express the relation as
i) a table
ii) a graph
iii) a mapping
Then, state the domain and range of the relation.
Problem 1 :
{(-2, 1), (-1, 0), (1, 2), (2, -4), (4, 3)}
Problem 2 :
{(-3, -3), (-1, 1), (0, 2), (2, -3), (2, 3)
Problem 3 :
{(-1, -1), (1, 1), (2, 1), (3, 2)}
Problem 4 :
{(3, -2), (1, 0), (-2, 4), (3, 1)}
Problem 5 :
{(0, 4), (-4, -4), (-2, 3), (4, 0)}
1)
a)
x -2 -1 1 2 4 |
y 1 0 2 -4 3 |
Graph :
Mapping a diagram :
Domain = {-2, -1, 1, 2, 4}
Range :
{1, 0, 2, -4, 3}
2) Table :
If x = -3 and y = -3
x = -1 and y = 1
x = 0 and y = 2
x = 2 and y = -3
x = 2 and y = 3
Graph :
Domain :
{-3, -1, 0, 2}
Range :
{-3, 1, 2, 3}
This relation is not a function.
3)
Table :
If x = -1 and y = -1
x = 1 and y = 1
x = 2 and y = 1
x = 3 and y = 2
Graph :
Mapping a diagram :
Domain :
(-1, 1, 2, 3)
Range :
(-1, 1, 2)
4)
Table :
If x = 3 and y = -2
x = 1 and y = 0
x = -2 and y = 4
x = 3 and y = 1
Graph :
Mapping a diagram :
Domain :
{3, 1, -2}
Range :
{-2, 0, 4, 1}
5)
Table :
If x = 0 and y = 4
x = -4 and y = -4
x = -2 and y = 3
x = 4 and y = 0
Graph :
Mapping a diagram :
Domain :
{0, -4, -2, 4}
Range :
{-4, 0, 3, 4}
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM