By the Trapezoid Midsegment Theorem, the midsegment of a trapezoid is parallel to each base and its measure is one half the sum of the lengths of the bases.
Example 1 :
In the figure, YZ is the midsegment of trapezoid TWRV. Determine the value of x.
Solution :
Length of line segment YZ = length of (TW + VR)/2
8 = (14.8 + x)/2
8(2) = 14.8 + x
16 = 14.8 + x
x = 16 - 14.8
x = 1.2
So, length of line segment VR is 1.2
Example 2 :
Solve for x.
Solution :
2x + 0.75 = (2x - 5.5 + x + 16)/2
2x + 0.75 = (3x + 10.5)/2
2(2x + 0.75) = 3x + 10.5
4x + 1.5 = 3x + 10.5
Subtracting 3x and 1.5 on both sides.
4x - 3x = 10.5 - 1.5
x = 9
Example 3 :
Find the length of TU.
Solution :
TU = (LM + QP)/2
2x + 4 = (2x - 4 + 3x + 2)/2
2x + 4 = (5x - 2)/2
2(2x + 4) = 5x - 2
4x + 8 = 5x - 2
4x - 5x = -2 - 8
-x = -10
x = 10
TU = 2x + 4
TU = 2(10) + 4
TU = 20 + 4
TU = 24
Example 4 :
CD is the midsegment of trapezoid WXYZ.
a. What is the value of x?
b. What is XY?
c. What is WZ?
Solution :
CD = (WZ + XY)/2
22 = (x + 3 + 4x + 1)/2
44 = 5x + 4
40 = 5x
x = 40/5
x = 8
a) The value of x is 8.
b) XY = 4x + 1 = 4(8) + 1 = 32 + 1 XY = 33 |
c) WZ = x + 3 = 8 + 3 WZ = 11 |
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM