MATH KANGAROO GRADE 3 MATH PRACTICE

Problem 1 :

In the picture at the bottom you see a map. In the middle a piece is missing. The cat should be able to reach the milk, and the mouse must not meet each other. What should the piece in the middle look like ?

kangaroo-math-practice-q1
kangaroo-math-practice-q1op.png

Solution :

In option E, we have separate paths. So, these two will not meet each other.

Problem 2 :

A 40 minute long lesson began at 11 : 50 hours. Exactly in the middle of the lesson a bird flew into the class room. At what time did this happen ?

A)  11 : 30 hours       B)  12 : 00 hours      C)  12 : 10 hours

D)  12 : 20 hours        E)  12 : 30 hours

Solution :

Starts at 11 : 50 hours 

Duration of the lesson = 40  minutes

In the middle of the lesson means, after 20 minutes.

11 : 50 + 20 ==> 12 : 10 hours

So, the bird flew into the class room at 12 : 10 hours.

Problem 3 :

Which square contains 3 quadrilaterals, 3 circles and 4 hearts ?

kangaroo-math-practice-q3.png

Solution :

Option A  :

Number of squares = 3

Number of circles = 4

Number of hearts = 4

Option B :

Number of squares = 3

Number of circles = 4

Number of hearts = 3

Option C :

Number of squares = 2

Number of circles = 4

Number of hearts = 4

Option D :

Number of squares = 3

Number of circles = 3

Number of hearts = 4

So, option D is correct.

Problem 4 :

In a cafe the soup costs 4, the main course 9 and the desert 5. The three courses when ordered together cost 15. How many Euro's cheaper is this, than ordering the same three courses separately ?

A)  €3        B)  €4       C)  €5      D)  €6      E)  €7

Solution :

Cost of buying these three courses separately = 4 + 9 + 5

= 18

Cost of buying these three courses together = €15

Difference = 18 - 15

= €3

Problem 5 :

Six coins build a triangle, what is the smallest number of coins that must be moved to create the circle ?

kangaroo-math-practice-q5.png

A)  1        B)  2       C)  3      D)  4      E)  5

Solution :

kangaroo-math-practice-q5an.png

So, 2 coins to be moved up to get the shape circle.

Problem 6 :

Four friends each eat some ice cream. Mike eats more than Franz, Jaroslav eats more than Viet and Jaroslav eats less than Franz. Put the friends in order according to how much ice cream they have eaten. Begin with largest amount.

A)  Mike, Jaroslav, Veit, Franz

B)  Veit, Mike, Franz, Jaroslav

C)  Mike, Franz, Jaroslav, Veit

D)  Jaroslav, Veit, Mike, Franz

D)  Jaroslav, Mike, Veit, Franz

Solution :

Mike > Franz

Jaroslav > Viet and 

Jaroslav < Franz

Let us solve this problem with small assumption.

To make the first statement true,

M = 5  and F = 3

To make the second statement true,

= 7  and V = 4

To make the third statement true, the value of J should be greater than V and lesser than F.

  • If we V = 2 and J may be 3, 4, ......
  • V = 2, J = 4 if so, we increase the value of F.  If F = 6, then M = 7
  • So far M = 7, F = 6,  J = 4, V = 2

Mike > Franz  (7 > 6)

Jaroslav > Viet (4 > 2)

and Jaroslav < Franz (4 < 6)

Mike, Franz, Jaroslav and Viet

Option C is correct.

Problem 7 :

I have tiles that look like this 

kangaroo-math-practice-q6.png

Which pattern i cannot create with them ?

kangaroo-math-practice-q6op.png

Solution :

The dark line is not dividing the tile into two equal triangles. By observing this, option B does not match with this. So, option B is correct.

Problem 8 :

Eva is a centipede with exactly 100 feet. Yesterday she bought 16 pairs of shoes and wore them straight away. Even so she still had 14 feet with no shoes. On how many feet did she already wear shoes before going shopping yesterday ?

A)  27        B)  40       C)  54      D)  70      E)  77

Solution :

Total number of feet = 100

Number of pairs bought = 16

Number of shoes they may wear in this = 16 x 2

= 32

Total number of feet  in which it dont wear shoes = 100 - 32

= 68

Number of shoes they dont wear shoes = 14

Number of feet she already wear shoes before going shopping yesterday = 68 - 14

= 54


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