Problem 1 :
Solution :
Dividing each term by cos2x
Let t = tan x
dt = sec2 x dx
When x = 0 and x = π/2
t = tan 0 ==> t = 0
t = tan π/2==> t = ∞
Problem 2 :
Solution :
Let t = cot x
dt = -cosec2 x dx
cosec2 x dx = -dt
When x = 0 and x = π/2
t = cot 0 ==> t = ∞
t = cot π/2 ==> t = 0
Problem 3 :
Solution :
Let t = tan x
dt = sec2x dx
When x = 0 and x = π/2
t = tan 0 ==> t = 0
t = tan π/2 ==> t = ∞
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM