Problem 1 :
a) 6ab² b) 52w |
c) 2r³s d) 7xyz |
Solution :
Decompose each expression into prime factors.
a) 6ab² = 2 ∙ 3 ∙ a ∙ b ∙ b b) 52w = 2 ∙ 2 ∙ 13 ∙ w |
c) 2r³s = 2 ∙ r ∙ r ∙ r ∙ s d) 7xyz = 7 ∙ x ∙ y ∙ z |
Variables :
The variables are the letters present in a monomial. That is, x, y, z,..
Coefficient :
The coefficient is the number that is multiplied by the variables. That is, 12x, 12y,..
Degree :
The degree is the sum of the exponents of the variables in a monomial.
That is, 12xy ---> Exponent of x is 1, Exponent of y is 1
So, the degree is 1 + 1 = 2
Problem 2 :
a) 11cd b) 19m3 c) 3f6 d) 21ab |
e) 5xy2 f) 35rs5 g) 2y4z3 h) 40m2n |
Solution :
a) Coefficient : 11 Variables : c, d Degree : 2 |
e) Coefficient : 5 Variables : x, y Degree : 3 |
b) Coefficient : 19 Variable : m Degree : 3 |
f) Coefficient : 35 Variables : r, s Degree : 6 |
c) Constant : 3 Variable : f degree : 6 |
g) Coefficient : 2 Variables : y, z Degree : 7 |
d) Coefficient : 21 Variables : a, b Degree : 2 |
h) Coefficient : 40 Variables : m, n Degree : 3 |
Problem 3 :
12m²n³, 70m³n
Solution :
Find the GCF of 12m²n³, 70m³n.
12m²n³ = 2 ∙ 2 ∙ 3 ∙ m ∙ m ∙ n ∙ n ∙ n
70m³n = 2 ∙ 5 ∙ 7∙ m ∙ m ∙ m ∙ n
= 2 ∙ m ∙ m ∙ n
GCF = 2m²n
Problem 4 :
72a³b², 86a
Solution :
Find the GCF of 72a³b², 86a.
72a³b² = 2 ∙ 2 ∙ 2 ∙ 3 ∙ 3 . a ∙ a ∙ a ∙ b ∙ b
86a = 2 ∙ 43 ∙ a
GCF = 2a
Problem 5 :
44m²n, 48mn²
Solution :
Find the GCF of 44m²n, 48mn².
44m²n = 2 ∙ 2 ∙ 11 ∙ m ∙ m ∙ n
48mn² = 2 ∙ 2 ∙ 2 ∙ 2 ∙ 3 ∙ m ∙ n ∙ n
= 2 ∙ 2 ∙ m ∙ n
GCF = 4mn
Problem 6 :
a²b³, ab³
Solution :
a²b³ = a ∙ a ∙ b ∙ b ∙ b
ab³ = a ∙ b ∙ b ∙ b
= a ∙ b ∙ b ∙ b
GCF = ab³
Problem 7 :
3x, 7xy²
Solution:
3x = 3 ∙ x
7xy² = 7 ∙ x ∙ y ∙ y
GCF = x
Problem 8 :
4rs², 27st³
Solution:
4rs² = 2 ∙ 2 ∙ r ∙ s ∙ s
27st³ = 3 ∙ 3 ∙ 3 ∙ s ∙ t ∙ t ∙ t
GCF = s
Problem 9 :
18wx², 45wx
Solution:
18wx² = 2 ∙ 3 ∙ 3 ∙ w ∙ x ∙ x
45wx = 3 ∙ 3 ∙ 5 ∙ w ∙ x
= 3 ∙ 3 ∙ w ∙ x
GCF = 9wx
Problem 10 :
12y², 15y³, 5y
Solution:
12y² = 2 ∙ 2 ∙ 3 ∙ y ∙ y
15y³ = 3 ∙ 5 ∙ y ∙ y ∙ y
5y = 5 ∙ y
GCF = y
Problem 11 :
rs³, s³t, r²st²
Solution :
rs³ = r ∙ s ∙ s ∙ s
s³t = s ∙ s ∙ s ∙ t
r²st² = r ∙ r ∙ s ∙ t ∙ t
GCF = s
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM