HOW TO FIND THE CENTROID OF A TRIANGLE

Find coordinates of the centroid of each triangle.

Problem 1 :

centroidq1

Solution:

Vertices X(0, 3), Y(-6, 0) and Z(0, 0)

Formula to find centroid of a triangle is

= (x1+x2+x3)3,(y1+y2+y3)3x1=0,x2=-6 and x3=0y1=3,y2=0 and y3=0= (0-6+0)3,(3+0+0)3= -63,33= (-2,1)

So, the centroid of the given triangle is (-2, 1).

Problem 2 :

centroidq2

Solution:

Vertices D(-5, 0), E(0, 6) and F(2, 0)

Formula to find centroid of a triangle is

= (x1+x2+x3)3,(y1+y2+y3)3x1=-5,x2=0 and x3=2y1=0,y2=6 and y3=0= (-5+0+2)3,(0+6+0)3= -33,63= (-1,2)

So, the centroid of the given triangle is (-1, 2).

Problem 3 :

centroidq3

Solution:

Vertices P(0, 6), Q(-3, 0) and R(-6, 6)

Formula to find centroid of a triangle is

= (x1+x2+x3)3,(y1+y2+y3)3x1=0,x2=-3 and x3=-6y1=6,y2=0 and y3=6= (0-3-6)3,(6+0+6)3= -93,123= (-3,4)

So, the centroid of the given triangle is (-3, 4).

Problem 4 :

centroidq4

Solution:

Vertices K(5, 0), L(-2, 0) and M(0, -6)

Formula to find centroid of a triangle is

= (x1+x2+x3)3,(y1+y2+y3)3x1=5,x2=-2 and x3=0y1=0,y2=0 and y3=-6= (5-2+0)3,(0+0-6)3= 33,-63= (1,-2)

So, the centroid of the given triangle is (1, -2).

Find the coordinates of the centroid of each triangle given the three vertices.

Problem 5 :

C(-7, -6), B(-8, 0), A(0,0)

Solution:

Formula to find centroid of a triangle is

= (x1+x2+x3)3,(y1+y2+y3)3x1=-7,x2=-8 and x3=0y1=-6,y2=0 and y3=0= (-7-8+0)3,(-6+0+0)3= -153,-63= (-5,-2)

So, the centroid of the triangle is (-5, -2).

Problem 6 :

S(0, -6), R(-10, -6), Q(1,0)

Solution:

Formula to find centroid of a triangle is

= (x1+x2+x3)3,(y1+y2+y3)3x1=0,x2=-10 and x3=1y1=-6,y2=-6 and y3=0= (0-10+1)3,(-6-6+0)3= -93,-123= (-3,-4)

So, the centroid of the triangle is (-3, -4).

Problem 7 :

T(0, 0), U(1, 3), V(-2,0)

Solution:

Formula to find centroid of a triangle is

= (x1+x2+x3)3,(y1+y2+y3)3x1=0,x2=1 and x3=-2y1=0,y2=3 and y3=0= (0+1-2)3,(0+3+0)3= -13,33= -13,1

So, the centroid of the triangle is (-1/3, 1).

Problem 8 :

Y(3, 4), X(-5, 0), W(0,0)

Solution:

Formula to find centroid of a triangle is

= (x1+x2+x3)3,(y1+y2+y3)3x1=3,x2=-5 and x3=0y1=4,y2=0 and y3=0= (3-5+0)3,(4+0+0)3= -23,43

So, the centroid of the triangle is (-2/3, 4/3).

Problem 9 :

Two vertices of a triangle are (0, 0) and (9, 0). The centroid is (6, 1). Find the third vertex of the triangle.

Solution:

Given vertices of triangle (0, 0), (9, 0) (x3, y3) and G(6, 1)

G(x, y)= (x1+x2+x3)3,(y1+y2+y3)3x1=0,x2=9y1=0,y2=0 6 = (0+9+x3)318=9+x3x3=91=(0+0+y3)3y3=3

Hence, the third vertex of the triangle is (9, 3).

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