HOW TO FIND RADIUS OF CIRCLE WITH 2 END POINTS

Problem 1 :

The endpoints of diameter of circle are (2, 4) and (-3, -1). Find the radius of the circle ?

Solution :

Let the given points be A(2, 4) and B(-3, -1).

Distance between two end points of the diameter = diameter of the circle

Length of AB / 2 ==> Radius of the circle

d = (x2 -x1)2 + (y2-y1)2Length of AB = (-3-2)2 + (-1-4)2Length of diamter = (-5)2 + (-5)2= 25 + 25= 50= 5 2

Problem 2 :

Find the coordinate of center of the circle passing through the points A(1, 2), B(3, -4) and C(5, -6). Also find the radius of the circle ?

Solution :

Let the center point be O(a, b)

Distance between 

OA = OB = OC  (radii of circle)

OA = (a-1)2 + (b-2)2OB = (a-3)2 + (b+4)2OC = (a-5)2 + (b+6)2OA = OB (a-1)2 + (b-2)2 = (a-3)2 + (b+4)2(a-1)2 + (b-2)2=(a-3)2 + (b+4)2a2-2a+1+b2-4b+4 = a2-6a+9+b2+8b+16-2a-4b + 5 = -6a+8b+254a-12b = -5 + 254a-12b = 20a - 3b = 4 ------(1)OA = OC (a-1)2 + (b-2)2 = (a-5)2 + (b+6)2(a-1)2 + (b-2)2=(a-5)2 + (b+6)2a2-2a+1+b2-4b+4 = a2-10a+25+b2+12b+36-2a-4b + 5 = -10a+12b+618a-16b = 61-58a - 16b = 56a-2b = 7 ------(2)

(1) - (2)

(a - 3b) - (a - 2b) = 4 - 7

-3b + 2b = -3

b = 3

Applying the value of b in (1), we get

a - 3(3) = 4

a = 4 + 9

a = 13

So, the center is O(13, 3).

Distance between O and A= (13-1)2 + (3-2)2= 122+12= 144+1Radius of the circle= 145

Problem 3 :

If the diameter of the circle of length 10 units which is having endpoints 

A(0, −3) and B(8, p)

find the possible values of p.

Solution :

Length of diameter= (8-0)2 + (p+3)210= 82+(p+3)2Taking square on both sides, we get102= 64 + (p+3)2100 = 64 +p2+6p+9p2+6p -27 = 0(p+9)(p-3)= 0p = -9 and p = 3

Problem 4 :

If the points A(4, 3) and B(x, 5) are on the circle with center O(2, 3). Find the value of x.

Solution :

Distance between center and point of the boundary will be the measure of radius.

Length of AO= (2-4)2 + (3-3)2= (-2)2+(0)2= 4= 2 --(1)Length of BO= (2-x)2 + (3-5)2= (2-x)2+(-2)2= (2-x)2+4---(2)(1) = (2)2 = (2-x)2+44 = 22-4x+x2+4

x- 4x + 8 - 4 = 0

x- 4x + 4 = 0

(x - 2)(x - 2) = 0

x = 2 and x = 2

Problem 5 :

The center of the circle is (2a - 1, 3a + 1) and it passes through the point (-3, -1). If the diameter of the circle is of length 20 units, find the value of a.

Solution :

Distance between center and the point (-3, -1) = radius of the circle 

radius = 20/2 ==>  10

So, the value of a is 2.

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