HOW TO FIND MISSING NUMBERS IN EQUIVALENT FRACTIONS

Write the missing numbers in the boxes to make each equation true.

Problem 1 :

Solution :

Problem 2 :

Solution :

Problem 3 :

Solution :

Problem 4 :

Solution :

The fraction 2/3 is multiplied by another fraction, so we get the fraction with the numerator 6. 

By considering the second fraction, its denominator is 3. So, the numerator will also be 3.

Problem 5 :

Solution :

The fraction 3/8 is multiplied by another fraction, so we get the fraction with the numerator 15. 

By considering the second fraction, its numerator is 5. So, the numerator will also be 5.

Problem 6 :

Solution :

To get denominator 12 from 6, we have to multiply 6 by 2. To get numerator 10, we have to multiply 5 by 2.

(5 ∙ 2) / (6 ∙ 2) = 10/12

Problem 7:

Solution :

To get numerator 15 from 5, we have to multiply 5 by 3. And to get denominator 24, we have to multiply 8 by 3.

(5 ∙ 3) / (8 ∙ 3) = 15/24

Problem 8 :

Solution:

For the second fraction, since the numerator is 4 the denominator should also be 4. So,

(2/__) x (4/4) = 8/12

Now we have to fix the denominator of the first fraction. 3 should be multiplied by 4, then we will get the denominator 12.

(2 ∙ 4) / (3 ∙ 4) = 8/12

Problem 9 :

Solution :

For the second fraction, since the numerator is 2 the denominator should also be 2. So,

(___/8) x (2/2) = __/16

Now we have to fix the numerator of the first fraction. We can fix any value as the numerator of the first fraction,

(3 ∙ 2) / (8 ∙ 2) = 6/16