HOW TO FIND LEAST COMMON MULTIPLE ALGEBRAIC TERMS

To find the least common multiple of algebraic expressions, we have to follow the steps given below.

Step 1 :

Break down the coefficients and write down it as product of prime factors.

Step 2 :

Write down the factors in exponential form.

Step 3 :

In common term, choose the highest exponents and if we find some thing extra, include that also.

Step 4 :

The product of these will be the least common multiple.

Problem 1 :

18, 6v

Solution:

18, 6v

18 = 32 × 2

6v = 2 × 3 × v

Least common multiple of 18, 6 is 32 ⋅ 2 

= 18v

So, the required LCM is 18v.

Problem 2 :

3x2, 10

Solution:

3x2, 10

3x2 = 3 × x × x

10 = 2 × 5

Least common multiple of 3, 10 is 2 ⋅ 3 ⋅ 5

= 30x2

So, the required LCM is 30x2.

Problem 3 :

30ab2, 50b2

Solution:

30ab2 = 3 × 2 × 5 × a × b × b

50b2 = 52 × 2 × b × b

Least common multiple of 30, 50 is 52 ⋅ 2 ⋅ 3

= 150ab2

So, the required LCM is 150ab2.

Problem 4 :

30xy3, 20y3

Solution:

30xy3 = 2 × 3 × 5 × x × y × y × y

20y3 = 2× 5 × y × y × y

Comparing y terms (LCM) is y3

Least common multiple of 30, 20 is 2⋅ 5 ⋅ 3

= 60xy3

Problem 5 :

20y, 14y2

Solution:

20y = 22 × 5 × y

14y2 = 2 × 7 × y × y

Least common multiple of 20, 14 is 22 ⋅ 5 ⋅ 7

= 140y2

Problem 6 :

25x2, 25y

Solution:

25x2 = 52 × x × x

25y = 52 × y

LCM = 52 × x2y

= 25x2y

Problem 7 :

21b, 45ab

Solution:

21b = 7 × 3 × b

45ab = 32 × 5 × a × b

Least common multiple of 21, 45 is 32 ⋅ 5 ⋅ 7

= 315ab

Problem 8 :

38x2, 18x

Solution:

38x2 = 2 × 19 × x × x

18x = 32 × 2 × x

Least common multiple of 38, 18 is 32 ⋅ 2 ⋅ 19

= 342x2

Problem 9 :

32u2, 14v2

Solution:

32u2 = 2× 22 × 2 × u × u

14v2 = 2 × 7 × v × v

Least common multiple of 32, 14 is 22 ⋅ 22 ⋅ 2 ⋅ 7

= 224u2v2

Problem 10 :

18m2, 24nm

Solution:

18m2 = 3× 2 × m × m

24nm = 22 × 2 × 3 × n × m

Least common multiple of 18, 24 is 3⋅ 22 ⋅ 2 

= 72m2n

Problem 11 :

36m4, 9m2, 18nm2

Solution:

36m4 = 2× 32 × m × m × m × m

9m2 = 32 × m × m

18nm2 = 3× 2 × n × m × m

Least common multiple of 36, 9, 18 is 32 ⋅ 22 

= 36nm4

Problem 12 :

36m2n2, 30n2, 36n4

Solution:

36m2n2 = 22 × 3× m × m × n × n

30n2 = 2 × 5 × 3 × n × n

36n4 =  22 × 32 × n × n × n × n

Least common multiple of 36, 30 is 32 ⋅ 22 ⋅ 5

= 180n4m2

Problem 13 :

16x2y, 32x

Solution:

16x2y = 22 × 22 × x × x × y

32x = 22 × 22 × 2 × x

Least common multiple of 16, 32 is 22 ⋅ 22 ⋅ 2

= 32x2y

Problem 14 :

30ab3, 20ab3

Solution:

30ab3 = 2 × 3 × 5 × a × b × b × b

20ab3 = 22 × 5 × a × b × b × b 

Least common multiple of 30, 20 is 22 ⋅ 5 ⋅ 3

= 60ab3

Problem 15 :

10ba, 20ba, 28ba

Solution:

10ba = 2 × 5 × b × a

20ba = 22 × 5 × b × a

28ba =  22 × 7 × b × a

Least common multiple of 10, 20, 28 is 22 ⋅ 5 ⋅ 7

= 140ba

Problem 16 :

8y2, 16xy, 16y

Solution:

8y2 = 22 × 2 × y × y

16xy = 22 × 2× x × y

16y = 22 × 2× x

Least common multiple of 8, 16, 16 is 2⋅ 22

= 16y2x

Problem 17 :

28b2, 20ab3, 16b4

Solution:

28b2 = 22 × 7 × b × b

20ab3 = 22 × 5 × a × b × b × b

16b4 = 22 × 22 × b × b × b × b

Least common multiple of 28, 20, 16 is 2⋅ 22 ⋅ 7 ⋅ 5

= 560b4a

Problem 18 :

12xy2, 39y3

Solution:

12xy2 = 22 × 3 × x × y × y

39y3 = 3 × 13 × y × y × y

Least common multiple of 12, 39 is 2⋅ 3 ⋅ 13

= 156xy3

Problem 19 :

33u, 9v2u

Solution:

33u = 3 × 11 × u

9v2u = 32 × v × v × u

Least common multiple of 33, 9 is 32 ⋅ 11 

= 99v2u

Problem 20 :

30yx, 24y2x

Solution:

30yx = 2 × 3 × 5 × y × x

24y2x = 22 × 2 × 3 × y × y × x

Least common multiple of 30, 24 is 22 ⋅ 2 ⋅ 3 ⋅ 5

= 120y2x

Problem 21 :

30v, 40u2v

Solution:

30v = 2 × 3 × 5 × v

40u2v = 22 × 2 × 5 × u × u × v

Least common multiple of 30, 40 is 22 ⋅ 2 ⋅ 3 ⋅ 5

= 120u2v

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