HOW TO FIND AREA AND PERIMETER OF SIMILAR FIGURES

If two shapes are similar, then their perimeter are proportional to the measures of the corresponding sides.

More simply, if two shapes are in the ratio a : b, then its perimeter will also be in the ratio a : b.

If two shapes are in the ratio a : b, then its area will be in the ratio a2 : b2

Problem 1 :

Triangle HIJ is similar to triangle STR, what is the perimeter of triangle STR

Solution :

Since the given sides are similar,

  • HI and ST are corresponding sides.
  • IJ and TR are corresponding sides.
  • HJ and SR are corresponding sides.

HI : ST = 4 : 10

HI : ST = 2 : 5

IJ : TR = 2 : 5

6 : TR = 2 : 5

6/TR = 2/5

TR = 15

HJ : SR = 2 : 5

HJ : 12 = 2 : 5

HJ/12 = 2/5

HJ = 24/5

Perimeter of STR :

= ST + TR + SR

= 10 + 15 + 12

= 37

Problem 2 :

If the two triangles are similar

Find

i) Scale factor

ii) Ratio of perimeter

iii)  Ratio of area

Solution :

The sides which are having side lengths 21 and 7, they are corresponding sides.

The sides lengths 15 and 5 are corresponding, then 18 and 6 are corresponding.

Ratio = 21 : 7 ==> 3 : 1

i) Scale factor = 3 : 1

ii)  Ratio of perimeter = 3 : 1

iii)  Ratio of area = 32 : 12

Problem 3 :

Two triangles have a scale factor of 2/3. The area of the larger triangle is 12 cm2. What is the area of smaller triangle.

Solution :

Area of smaller triangle / Area of larger triangle = (2/3)2

Area of larger triangle = 12 cm2

Area of smaller triangle / 12 = (2/3)2

Area of smaller triangle = 12 (4/9)

Area of smaller triangle = 5.3 cm2

Problem 4 :

If the length of each side of triangle is cut to 1/3 of its original size, what happens to the area of the triangle ?

The new area is _______________ of the original area.

Solution :

From the given information, every side is being divided into 1/3 of the original size. So, the ratio is 1 : 3.

Relationship between scale factor and area :

Area of smaller triangle : Area of larger triangle = (1 : 3)2

Area of smaller triangle : Area of larger triangle = 1 : 9

Area of smaller triangle = (1/9) of area of larger triangle.

Problem 5 :

For the two triangles below to be similar, which of the following be true ?

a)  x = 2y/3    b)  c = 3y/2     c)  x = 3y     d)  x = y

Solution :

Since the given shapes are similar,

EF : KJ ==> 6 : 9 ==> 2 : 3

FG : KL ==> x : y

x : y = 2 : 3

x/y = 2/3

x = 2y/3

Problem 6 :

An architect is building a model of a tennis court for a new client. On the model, the court is 6 inches wide and 13 inches long. An official tennis court is 36 feet wide. What is the length of a tennis court ?

Solution :

Let x be the length of tennis court.

Since the shapes are similar, the ratio between model to official tennis court is 

6 : 13 = 36 : x

6/13 = 36/x

6x = 36(13)

x = 36(13)/6

x = 6 (13)

x = 78

So, length of official tennis court is 78 feet.

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