FROM THE GRAPH OF THE FUNCTION FIND THE GRAPH OF ITS DERIVATIVE

How to match the graph of function f(x) to its derivative graph ?

The following points to be noted from the graph of original function.

  • If the given function f(x) is increasing on the interval, then its derivative function will have positive slope and that should be above the x-axis.
  • If the given function f(x) is decreasing on the interval, then its derivative function will have negative slope and that should be below the x-axis.
  • The values that we are deriving by equating the first derivative to 0, that is f'(x) = 0 are critical numbers. These critical numbers are x-intercepts in the derivative graph.
graph-of-f-of-x-and-its-derivativeq1

From graph of f(x)

(-∞, 0) --> Increasing

(0, 2) --> Decreasing

(2, ∞) --> Increasing

At x = 0 and x = 2, there are critical numbers

From graph of f'(x)

(-∞, 0) --> above the x-axis

(0, 2) --> below the x-axis

(2, ∞) --> above the x-axis

At x = 0 and x = 2, there are x-intercepts

graph-of-f-of-x-and-its-derivativeq2.png

The graph of a function is given. Choose the answer that represents the graph of its derivative.

Problem 1 :

graph-of-x-to-its-derivativeq1
graph-of-x-to-its-derivativeq1s.png

Solution :

In the question, the given curve is a parabola which will have the highest exponent of 2. So, its derivative will have the highest exponent of 1. Then it must be a straight line.

  • On the interval (-∞, 0), the function is decreasing.
  • On the interval (0, ∞), the function is increasing.

In the derivative graph the curve should be below the x-axis in the interval (-∞, 0).

In the derivative graph the curve should be above the x-axis in the interval (0, ∞).

So, option C is correct.

Problem 2 :

graph-of-x-to-its-derivativeq2.png
graph-of-x-to-its-derivativeq2s.png

Solution :

Let us assume that the curve is intersecting x-axis on -1 and 1. It is clearly show it intersects the origin also.

From graph of f(x)

(-∞, -1) --> Increasing

(-1,1) --> Decreasing

(1, ∞) --> Increasing

At x = -1 and x = 1, there are critical numbers

graph of f'(x) will be

(-∞, -1) --> above x-axis

(-1, 1) --> below x-axis

(1, ∞) --> above x-axis

At x = -1 and x = 1, there are x-intercepts

So, option C is correct.

Problem 3 :

graph-of-f-of-x-and-its-derivativeq3.png
graph-of-f-of-x-and-its-derivativeq3s.png

Solution :

From graph of f(x)

(-∞, 0) --> Decreasing

(0, ) --> Increasing 

At x = 0 there is

a critical number

graph of f'(x) will be

(-∞, 0) --> below x-axis

(0, ∞) --> above x-axis

At x = 0 there is a x-intercept

Both option B and D satisfies the above conditions, but considering the slope from the given graph it is very closer to 1. So, option D is correct.

Problem 4 :

graph-of-f-of-x-and-its-derivativeq4.png
graph-of-f-of-x-and-its-derivativeq4s.png

Solution :

From graph of f(x)

(-∞, -5) --> Increasing

(-5, 0) --> Decreasing

(0, 5) --> Increasing

(5, ∞) --> Decreasing

Critical numbers are -5, 0, 5

graph of f'(x) will be

(-∞, -5) --> above x-axis

(-5, 0) --> below x-axis

(0, 5) --> above x-axis

(5, ∞) --> below x-axis

x-intercepts are -5, 0 and 5.

So, option D is correct.

Problem 5 :

graph-of-f-of-x-and-its-derivativeq5.png
graph-of-f-of-x-and-its-derivativeq5s.png

Solution :

From graph of f(x)

(-∞, -11) --> Decreasing

(-11, 1) --> Increasing

(1, ∞) --> Decreasing

Critical numbers are -11, 1

graph of f'(x) will be

(-∞, -11) --> below x-axis

(-11, 1) --> above x-axis

(1, ∞) --> below x-axis

x-intercepts are -11 and 1

So, option C is correct.

Problem 6 :

Given the graph of f, find any values of x which f' is not defined.

graph-of-f-of-x-and-its-derivativeq6.png

A)  -3, 3    B)  -2, 2      C)  -3, 0, 3    D)  -2, 0, 2

Solution:

At x = -2 and x = 2, we have sharp points. At sharp points its derivative is not defined. So, option B is correct.

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