How to match the graph of function f(x) to its derivative graph ?
The following points to be noted from the graph of original function.
From graph of f(x) (-∞, 0) --> Increasing (0, 2) --> Decreasing (2, ∞) --> Increasing At x = 0 and x = 2, there are critical numbers |
From graph of f'(x) (-∞, 0) --> above the x-axis (0, 2) --> below the x-axis (2, ∞) --> above the x-axis At x = 0 and x = 2, there are x-intercepts |
The graph of a function is given. Choose the answer that represents the graph of its derivative.
Problem 1 :
Solution :
In the question, the given curve is a parabola which will have the highest exponent of 2. So, its derivative will have the highest exponent of 1. Then it must be a straight line.
In the derivative graph the curve should be below the x-axis in the interval (-∞, 0).
In the derivative graph the curve should be above the x-axis in the interval (0, ∞).
So, option C is correct.
Problem 2 :
Solution :
Let us assume that the curve is intersecting x-axis on -1 and 1. It is clearly show it intersects the origin also.
From graph of f(x) (-∞, -1) --> Increasing (-1,1) --> Decreasing (1, ∞) --> Increasing At x = -1 and x = 1, there are critical numbers |
graph of f'(x) will be (-∞, -1) --> above x-axis (-1, 1) --> below x-axis (1, ∞) --> above x-axis At x = -1 and x = 1, there are x-intercepts |
So, option C is correct.
Problem 3 :
Solution :
From graph of f(x) (-∞, 0) --> Decreasing (0, ∞) --> Increasing At x = 0 there is a critical number |
graph of f'(x) will be (-∞, 0) --> below x-axis (0, ∞) --> above x-axis At x = 0 there is a x-intercept |
Both option B and D satisfies the above conditions, but considering the slope from the given graph it is very closer to 1. So, option D is correct.
Problem 4 :
Solution :
From graph of f(x) (-∞, -5) --> Increasing (-5, 0) --> Decreasing (0, 5) --> Increasing (5, ∞) --> Decreasing Critical numbers are -5, 0, 5 |
graph of f'(x) will be (-∞, -5) --> above x-axis (-5, 0) --> below x-axis (0, 5) --> above x-axis (5, ∞) --> below x-axis x-intercepts are -5, 0 and 5. |
So, option D is correct.
Problem 5 :
Solution :
From graph of f(x) (-∞, -11) --> Decreasing (-11, 1) --> Increasing (1, ∞) --> Decreasing Critical numbers are -11, 1 |
graph of f'(x) will be (-∞, -11) --> below x-axis (-11, 1) --> above x-axis (1, ∞) --> below x-axis x-intercepts are -11 and 1 |
So, option C is correct.
Problem 6 :
Given the graph of f, find any values of x which f' is not defined.
A) -3, 3 B) -2, 2 C) -3, 0, 3 D) -2, 0, 2
Solution:
At x = -2 and x = 2, we have sharp points. At sharp points its derivative is not defined. So, option B is correct.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM