Find the standard form of the equation of each hyperbola.
Problem 1 :
Foci (0, ±4), vertices (0, ±2)
Solution:
Foci = (0, ±4)
= (0, ±c)
c = 4
vertices = (0, ±a)
= (0, ±2)
a = 2
b2 = c2 - a2
= 42 - 22
= 16 - 4
b2 = 12
So, the equation of hyperbola is
Problem 2 :
Vertices (±4, 0), Asymptotes: y = ±3x
Solution:
Vertices (4, 0) (-4, 0)
The hyperbola is the horizontal transverse axis type.
Vertices = (±a, 0)
a = 4
So, the equation of hyperbola is
Problem 3 :
Endpoints of transverse axis: (±6, 0), Asymptotes: y = ±2x
Solution:
The hyperbola is the horizontal transverse axis type.
Here a = 6
So, the equation of hyperbola is
Problem 4 :
Foci (0, ±3), length of transverse axis 2
Solution:
Foci = (0, ±c)
c = 3
length of transverse axis 2a = 2
a = 1
b2 = c2 - a2
= 32 - 12
= 9 - 1
b2 = 8
So, the equation of hyperbola is
Problem 5 :
Solution:
From given graph,
Center (h, k) = (2, 1)
Vertices = (4, 1) (0, 1)
a = 2
b = 3
So, the equation of hyperbola is
Problem 6 :
Solution:
From given graph,
Center (h, k) = (0, 0)
Vertices = (3, 0) (-3, 0)
a = 3
b = 1
So, the equation of hyperbola is
May 21, 24 08:51 PM
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