Form quadratic equations with the following given numbers as its roots.
Problem 1 :
3 + i , 3 – i
Solution :
α = 3 + i and β = 3 - i
α + β = 3 + i + 3 - i α + β = 6 |
α β = (3 + i) (3 - i) α β = 32 - i2 α β = 9 - (-1) α β = 10 |
x2 - 6x + 10 = 0
Form quadratic equations with the following given numbers as its roots.
Problem 2 :
4 + 5i, 4 - 5i
Solution :
α = 4 + 5i and β = 4 - 5i
α + β = 4 + 5i + 4 - 5i α + β = 8 |
α β = (4 + 5i) (4 - 5i) α β = 42 - (5i)2 = 16 -25(-1) = 16 + 25 = 41 |
Problem 3 :
Find a quadratic polynomial whose zeroes are 2 + √3 and 2 – √3
Solution :
Here α = 2 + √3 and β = 2 – √3
α + β = 2 + √3 + 2 – √3 ==> 4
α β = (2 + √3)(2 – √3)
= 22 - √32
= 4 - 3
= 1
x2 - 4x + 1 = 0
So, the required polynomial is x2 - 4x + 1 = 0.
Problem 4 :
What is an equation whose roots are 5+√2 and 5−√2
Solution :
α = 5+√2, β = 5-√2
α + β = 5 + √2 + 5 - √2
α + β = 10
αβ = (5+√2) (5-√2)
αβ = 52-√22
= 25 - 2
= 23
x2 - (α + β) x + α β = 0
x2 - 10x + 23 = 0
Problem 5 :
Find the quadratic polynomial with rational coefficients which has 1/(3+2√2) as a root.
Solution :
x2 - 6x + 1 = 0
Problem 6 :
Form quadratic equations with the following given numbers as its roots.
2 + √3, 2 - √3
Solution :
α = 2 + √3, β = 2 - √3
α + β = 2 + √3 + 2 - √3
α + β = 4
αβ = (2 + √3) (2 - √3)
αβ = 22-√32
= 4 - 3
= 1
x2 - (α + β) x + α β = 0
x2 - 4x + 1 = 0
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM