Problem 1 :
Determine the equation of a quadratic function that has a minimum at (-2, -3) and passes through (-1, 1).
Problem 2 :
Determine the equation of a quadratic function that has a maximum at (2, 10) and passes through (1, 8).
Problem 3 :
Find the minimum of the parabola: y = 2x2 + 8x + 9
(a) (-2, 1) (b) (2, 33) (c) (2, 17)
(d) (-2, -17) (e) None of these
Problem 4 :
Find the maximum of the parabola: y = -3x2 + 12x + 1
(a) (6, -5) (b) (-2, -19) (c) (2, 13)
(d) (1, 14) (e) None of these
Problem 5 :
The graph of y = x2 is shown in the standard (x, y) coordinate plane below. For which of the following equations is the graph of the parabola shifted 3 units to the right and 2 units down?
A) y = (x + 3)2 - 2 B) y = (x - 3)2 - 2
C) y = (x + 3)2 + 2 D) y = (x - 3)2 + 2
Problem 6 :
The height of a bridge is given by the equation y = -3x2 + 12x, where y is the height of the bridge (in miles) and x is the number of miles from the base of the bridge.
i. How far from the base of the bridge does the maximum height occur?
ii. What is the maximum height of the bridge?
A) i. 2 miles ii. 12 miles
B) i. -2 miles ii. 12 miles
C) i. 3 miles ii. 9 miles
D) i. 3 miles ii. 6 miles
1) y = 4x2 + 16x + 13
2) y = -2x2 + 8x + 2
3) the minimum value is (-2, 1).
4) the maximum value is (2, 13).
5) y = (x - 3)2 - 2
6) i) x = 2 miles and ii) y = 12 miles
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM