FINDING AVERAGE RATE OF CHANGE OF COMPOSITE FUNCTION

Definition of average rate of change :

The average rate of change between x = a and x = b is the slope of the secant line of the curve between the points x = a and x = b

Average rate of change =f(b)-f(a)b-a(or)Average rate of change =yx (or)Average rate of change =y2-y1x2-x1

The graphs of f and g are given below, for each function find the average rate of change of the given interval.

avg-rate-of-change-of-composite-fun

Problem 1 :

h(x) = f(x) + g(x) on [-4, 3]

Solution :

Here a = -4 and b = 3

h(a) = h(-4) = f(-4) + g(-4)

Output of f(-4) is 2, output of g(-4) is -2.

h(-4) = 2 + (-2)

h(-4) = 0

h(b) = h(3) = f(3) + g(3)

Output of f(3) is 0, output of g(3) is 4.

h(3) = 0 + 4

h(3) = 4

Average rate of change = h(b)-h(a)b-a = h(3)-h(-4)3-(-4)= 4-03-(-4)= 43+4= 47

Problem 2 :

k(x) = f(g(x)) on [-4, 0]

Solution :

Here a = -4 and b = 0

k(a) = f(g(a)), then k(-4) = f(g(-4))

Output of g(-4) is -2

k(-4) = f(-2)

k(-4) = 3

k(b) = f(g(b)), then k(0) = f(g(0))

Output of g(0) is -1

k(0) = f(-1)

k(0) = 3

Average rate of change = k(b)-k(a)b-a = k(0)-k(-4)0-(-4)= 3-30-(-4)= 04=

Problem 3 :

w(x) = g(f(x)) on [-2, 3]

Solution :

Here a = -2 and b = 3

w(a) = g(f(a)), then k(-2) = g(f(-2))

Output of f(-2) is 3

w(-2) = g(3)

w(-2) = 4

k(b) = g(f(a)), then k(3) = g(f(3))

Output of f(3) is 0

w(0) = g(0)

w(0) = -1

Average rate of change = w(b)-w(a)b-a = -1-43-(-2)= -53+2= -55=

Problem 4 :

The graph shows the depth of water W in a reservoir over a one-year period as a function of the number of days x since the beginning of the year. What was the average rate of change of W between x = 100 and x = 200?

average-rate-of-change-from-graphq6.png

Solution :

(100, 75) and (200, 50)

Average rate of change = (50 - 75)/(200 - 100)

= -25/100

= -1/4

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