FIND THE PERIMETER OF EACH TRIANGLE

The Formula for the Perimeter of a Triangle,

Perimeter = a + b + c

(where a, b, and c are the sides of a triangle)

Problem 1 :

Solution :

Perimeter of triangle = a + b + c

Here, a = 4/7 m, b = 7/8 m and c = 9/8 m

= 4/7 m + 7/8 m + 9/8 m

= (4/7 + 7/8 + 9/8) m

LCM of 7, 8 and 8 is 56

= 32/56 + 49/56 + 63/56 m

= (144)/56 m

=18/7 m

Converting improper fraction into mixed fraction,

= 2  4/7 m

So, the perimeter of a triangle is 18/7 m or 2 4/7 m.

Problem 2 :

Solution :

Perimeter of triangle = a + b + c

Here a = 2/3 cm, b = 2/3 cm and c = 4/9 cm

= 2/3 cm + 2/3 cm + 4/9 cm

= (2/3 + 2/3 + 4/9) cm

LCM of 3, 3 and 9 is 9

= 6/9 + 6/9 + 4/9 cm

= 16/9 cm

Converting improper fraction into a mixed fraction,

= 1  7/9 cm

So, the perimeter of a triangle is 16/9 cm or 1 7/9 cm.

Problem 3 :

Solution :

Perimeter of triangle = a + b + c

Here a = 1 1/4 mm, b =1 1/4 mm and c =1 1/4 mm

=1 1/4 mm +1 1/4 mm +1 1/4 mm

= (5/4 + 5/4 + 5/4) mm

= 15/4 mm

= 3  3/4 mm

So, the perimeter of a triangle is 15/4 mm or 3 3/4 mm.

Problem 4 :

Solution :

Perimeter of triangle = a + b + c

Here a = 3/8 mm, b = 3/8 mm and c = 1/5 mm

= 3/8 mm + 3/8 mm + 1/5 mm

= (3/8 + 3/8 + 1/5) mm

LCM of 8, 8 and 5 is 40

= 15/40 + 15/40 + 8/40 mm

= 38/40 mm

= 19/20 mm

So, the perimeter of a triangle is 19/20 mm.

Problem 5 :

Solution :

Perimeter of triangle = a + b + c

Here a = 9/7 m, b = 9/7 m and c = 9/7 m

= 9/7 m + 9/7 m + 9/7 m

= (9/7 + 9/7 + 9/7) m

= 27/7 m

= 3  6/7 m

So, the perimeter of a triangle is 27/7 m or 3 6/7 m.

Problem 6 :

Solution :

Here a = 3 1/3 cm, b = 3/4 cm and c = 7/2 cm

= 3 1/3 cm + 3/4 cm + 7/2 cm

= (10/3 + 3/4 + 7/2) cm

LCM of 3, 4 and 2 is 12

= 40/12 + 9/12 + 42/12 cm

= 91/12 cm

= 7  7/12 cm

So, the perimeter of a triangle is 91/12 cm or 7 7/12 cm.

Problem 7 :

Solution :

Here a = 5/3 cm, b = 5/3 cm and c = 5/3 cm

= 5/3 cm + 5/3 cm + 5/3 cm

= (5/3 + 5/3 + 5/3) cm

= 15/3 cm

= 5 cm

So, the perimeter of a triangle is 5 cm. 

Problem 8 :

Solution :

Here a = 3 mm, b = 5/4 mm and c = 2 1/2 mm

= 3 mm + 5/4 mm + 2 1/2 mm

= (3 + 5/4 + 5/2) mm

= 3 + (5/4 + 5/2) 

= 3 + (15/4) 

= (12 + 15) / 4 

= 27/4 mm

= 6  3/4 mm

So, the perimeter of a triangle is 27/4 mm or 6  3/4 mm. 

Problem 9 :

Solution :

Here a = 2 m, b = 6/5 m and c = 6/5 m

= 2 m + 6/5 m + 6/5 m

= (2 + 6/5 + 6/5) m

= (2 + 12/5) m

= 22/5 m

= 4  2/5 m

So, the perimeter of a triangle is 22/5 m or 4  2/5 m.