FIND THE MISSING SIDES OF THE POLYGON IF EXTERIOR ANGLE GIVEN

Regular polygon has all sides equal in length and all angles equal in size.

The sum of interior angles of n sided polygon is 

s = (n - 2) x 180°

Measure of each angle= (n-2)×180n

Sum of exterior angles of any polygon is 360 degree.

Problem 1 :

Find the number of sides of a regular polygon whose each exterior angle measures 60°.

Solution :

Sum of all exterior angles = 360°

n × 60 = 360

n = 360/60

n = 6

Hence, the number of sides in the polygon is 6.

Problem 2 :

An exterior angle and the interior angle of a regular polygon are in the ratio 2:7. Find the number of sides of the polygon.

Solution :

Let x be the interior angle, then 180-x be the exterior angle.

(180-x) : x = 2 : 7

(180-x)/x = 2 / 7

2x = 7(180-x)

2x = 1260 - 7x

2x + 7x = 1260

9x = 1260

x = 1260/9

x = 40

Exterior angle is 40 degree. Interior angle = 140

Hence, the number of sides in the polygon is 9.

140 = (n-2)×180n 140n =(n - 2)×180140n = 180n-360360 = 180n - 140n360 = 40nn = 360/40n = 9

Problem 3 :

Each exterior angle of a regular polygon is 20⁰. Work out the number of sides of the polygon.

Solution :

Exterior angle of the regular polygon = 20

Each interior angle = 180 - 20

= 160

Measure of each interior angle = [(n - 2) 180]/n

160 = (180/n)(n - 2)

160n/180 = n - 2

8n/9 = n - 2

8n = 9(n - 2)

8n = 9n - 18

8n - 9n = -18

-n = -18

n = 18

So, the number of sides of the polygon is 18.

Problem 4 :

The number of sides of a regular polygon whose each exterior angle is 60° is

Solution :

Exterior angle of the regular polygon = 60

Each interior angle = 180 - 60

= 120

Measure of each interior angle = [(n - 2) 180]/n

120 = (180/n)(n - 2)

120n/180 = n - 2

2n/3 = n - 2

2n = 3(n - 2)

2n = 3n - 6

2n - 3n = -6

-n = -6

n = 6

So, the number of sides of the polygon is 6.

Problem 5 :

The interior angle of a regular polygon is four times its exterior angle. How many sides does the polygon have ?

Solution :

Let x be the interior angle, then 180 - x be the exterior angle.

x = 4(180 - x)

x = 720 - 4x

Adding 4x, we get

x + 4x = 720

5x = 720

x = 720/5

x = 144

Interior angle = 144.

Measure of each interior angle = [(n - 2) 180]/n

144 = (180/n)(n - 2)

1440n/180 = n - 2

4n/5 = n - 2

4n = 5(n - 2)

4n = 5n - 10

4n - 5n = -10

-n = -10

n = 10

So, the number of sides of the polygon is 10.

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