A trapezoid is also known as a trapezium is a four-sided polygon or a quadrilateral. It has one set of opposite sides which are parallel and a set of non-parallel sides.
The parallel sides are known as the bases and the non-parallel sides are known as the legs of the trapezoid.
Area of trapezoid = (1/2) h (a + b)
Here a and b area parallel sides and h is height.
Perimeter of the trapezoid = Sum of length of all sides.
Find x.
Problem 1 :
Solution :
So, the value of x is 6.
Problem 2 :
Solution :
Area of trapezoid A = (1/2) h (a + b)
Area = 88 ft2, a = 3 ft, b = 13 ft and h = x
88 = (1/2) ⋅ h (3 + 13)
Multiply by 2 on both sides
88 ⋅ 2 = x (16)
Divide by 16 on both sides.
(88 ⋅ 2)/16 = h
h = 11
Problem 3 :
Solution :
Area of trapezoid A = (1/2) h (a + b)
Area = 114 yd2, a = 4 yd, b = x and h = 19 yd
114 = (1/2) ⋅ 19 (4 + x)
(114 ⋅ 2) = 19 (4 + x)
Divide by 19 on both sides.
(114 ⋅ 2)/19 = 4 + x
4 + x = 12
Subtracting 4 on both sides.
x = 8
So, base length of the trapezoid is 8 yd.
Problem 4 :
Solution :
Area of trapezoid A = (1/2) h (a + b)
Area = 56 yd2, a = 14 yd, b = 2 yd and h = x
56 = (1/2) ⋅ x (14 + 2)
(56 ⋅ 2) = x (16)
Divide by 16 on both sides.
(56 ⋅ 2)/16 = x
x = 7 yd
So, height of the trapezoid is 7 yd.
Problem 5 :
Solution :
Area of trapezoid A = (1/2) h (a + b)
Area = 96 ft2, a = 6 ft, b = x and h = 8 ft
96 = (1/2) ⋅ 8 (6 + x)
96 = 4 (6 + x)
Divide by 4 on both sides.
96/4 = 6 + x
6 + x = 24
Subtracting 6 on both sides.
x = 24 - 6
x = 18 ft
Problem 6 :
Solution :
Area of trapezoid A = (1/2) h (a + b)
Area = 75 ft2, a = 7 ft, b = x and h = 5 ft
75 = (1/2) ⋅ 5 (7 + x)
Divide by 4 on both sides.
75/5 = (1/2) (7 + x)
(1/2) (7 + x) = 15
6 + x = 24
Subtracting 6 on both sides.
x = 24 - 6
x = 18 ft
Problem 7 :
Solution :
Area of trapezoid A = (1/2) h (a + b)
Area = 40 in2, a = 9 in, b = 11 in and h = x in
40 = (1/2) ⋅ x (9 + 11)
Multiply by 2 on both sides.
(40⋅2) = x(20)
Divide by 20 on both sides.
x = 2⋅2
x = 4 in
Problem 8 :
Solution :
Area of trapezoid A = (1/2) h (a + b)
Area = 50 yd2, a = 15 in, b = 10 yd and h = x yd
50 = (1/2) ⋅ x (15 + 10)
Multiply by 2 on both sides.
(50⋅2) = x(25)
Divide by 25 on both sides.
x = 100/25
x = 4 yd
Problem 9 :
Solution :
Area of trapezoid A = (1/2) h (a + b)
Area = 22 in2, a = 9 in, b = x and h = 4 in
22 = (1/2) ⋅ 4 (9 + x)
Multiply by 2 on both sides.
(22⋅2) = 4(9+x)
Divide by 4 on both sides.
9 + x = 44/4
x = 11 - 9
x = 2 in
x = 4 yd
May 21, 24 08:51 PM
May 21, 24 08:51 AM
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