Write each polynomial as the product of its greatest common monomial factor and a polynomial.
Problem 1 :
8x² + 12x
Solution :
8x² = 2 ∙ 2 ∙ 2 ∙ x ∙ x
12x = 2 ∙ 2 ∙ 3 ∙ x
Product of common factors:
= 2 ∙ 2 ∙ x
= 4x
Greatest common factor of 8x² + 12x is 4x.
Divide 8x² + 12x by 4x
8x²/4x = 2x |
2x/4x = 3 |
= 4x (2x + 3)
Problem 2 :
6a4 – 3a³ + 9a²
Solution :
6a4 = 3 ∙ 2 ∙ a ∙ a ∙ a ∙ a
3a³ = 3 ∙ a ∙ a ∙ a
9a² = 3 ∙ 3 ∙ a ∙ a
Product of common factors:
= 3 ∙ a ∙ a
= 3a²
Greatest common factor of 6a4 – 3a³ + 9a² is 3a².
Divide 6a4 – 3a³ + 9a² by 3a²
6a4/3a² = 2a² |
– 3a³/3a² = -a |
9a²/3a² = 3 |
So,
6a4 – 3a³ + 9a² = 3a² (2a² - a + 3)
Problem 3 :
5ab² - 15ab + 20a²b
Solution :
5ab² = 5 ∙ a ∙ b ∙ b
15ab = 5 ∙ 3 ∙ a ∙ b
20a²b = 5 ∙ 4 ∙ a ∙ a ∙ b
Product of common factors:
= 5 ∙ a ∙ b
= 5ab
Greatest common factor of 5ab² - 15ab + 20a²b is 5ab.
Divide 5ab² - 15ab + 20a²b by 5ab
5ab²/5ab = b |
-15ab/5ab = -3 |
20a²b/5ab = 4a |
So,
5ab² - 15ab + 20a²b = 5ab (b – 3 + 4a)
Problem 4 :
x³y³ - 2x³y² + x²y²
Solution :
x³y³ = x ∙ x ∙ x ∙ y ∙ y ∙ y
2x³y² = 2 ∙ x ∙ x ∙ x ∙ y ∙ y
x²y² = x ∙ x ∙ y ∙ y
Product of common factors:
= x ∙ x ∙ y ∙ y
= x²y²
Greatest common factor of x³y³ - 2x³y² + x²y² is x²y²
Divide x³y³ - 2x³y² + x²y² by x²y²
x³y³/ x²y² = xy |
- 2x³y²/ x²y² = -2x |
x²y²/ x²y² = 1 |
So,
x³y³ - 2x³y² + x²y² = x²y² (xy – 2x + 1)
Problem 5 :
4a – 12ab + 16a²
Solution :
4a = 2 ∙ 2 ∙ a
12ab = 2 ∙ 2 ∙ 3 ∙ a ∙ b
16a² = 2 ∙ 2 ∙ 2 ∙ 2 ∙ a ∙ a
Product of common factors:
= 2 ∙ 2 ∙ a
= 4a
Greatest common factor of 4a – 12ab + 16a² is 4a.
Divide 4a – 12ab + 16a² by 4a
4a/4a = 1 |
-12ab/4a = -3b |
16a²/4a = 4a |
So,
4a – 12ab + 16a² = 4a (1 – 3b + 4a)
Problem 6 :
21a² - 14a + 7
Solution :
21a² = 7 ∙ 3 ∙ a ∙ a
14a = 7 ∙ 2 ∙ a
7 = 7
Product of common factors:
= 7
Greatest common factor of 21a² - 14a + 7 is 7.
Divide 21a² - 14a + 7 by 7
21a²/7 = 3a² |
-14a/7 = -2a |
7/7 = 1 |
So,
21a² - 14a + 7 = 7 (3a² - 2a + 1)
May 21, 24 08:51 PM
May 21, 24 08:51 AM
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