To evaluate an algebraic expression means to find the value of the expression when the variable is replaced by a given number.
To evaluate an expression, we substitute the given number for the variable in the expression and then simplify
the expression using the order of operations.
Problem 1 :
If f(x) = 2x−5, then what is the value of f(2) + f(5) ?
(A) 1 (B) 2 (C) 3 (D) 4 (E) 5
Solution :
f(x) = 2x−5
f(2) + f(5) :
To find f(2), we apply x = 2 f(2) = 2(2) - 5 f(2) = 4 - 5 f(2) = -1 |
To find f(5), we apply x = 5 f(5) = 2(5) - 5 f(5) = 10 - 5 f(5) = 5 |
f(2) + f(5) = -1 + 5 ==> 4
Problem 2 :
If h(x) = 3x + 5 and h(a) = 27, then what is the value of a ?
Solution :
h(a) = 27
h(x) = 3x + 5
h(a) = 3a + 5
3a + 5 = 27
Solving for a, we get
3x = 27 - 5
3a = 22
a= 22/3
Problem 3 :
Let f(x) = 4x − 3. If f(a) = 9 and f(b) = 5, then what is f(a + b) ?
(A) 5 (B) 7 (C) 14 (D) 16 (E) 17
Solution :
f(x) = 4x − 3. If f(a) = 9 and f(b) = 5
f(a) = 9
4a - 3 = 9 -----(1)
Solving for a from (1), we get
4a = 12
a = 12/4 ==> a = 3
f(b) = 5
4b - 3 = 5 ------(2)
Solving for b from (2), we get
4b = 5 + 3
4b = 8
b = 2
f(a + b) = f(3 + 2) ==> f(5)
f(5) = 4(5) - 3
f(5) = 20 - 3
f(5) = 17
Problem 4 :
If f(x) = x2 − 1, and f(2a) = 35, then what could be the value of a ?
(A) −6 (B) −3 (C) 1 (D) 2 (E) 6
Solution :
f(x) = x2 − 1, and f(2a) = 35
f(2a) = (2a)2 - 1
4a2 - 1 = 35
4a2 = 36
a2 = 36/4
a2 = 9
a = 3 and -3
Accordingly the options, -3 is the answer.
Problem 5 :
If f(x) = 2x+ 4, then what is the value of f(4) + f(6) ?
(A) f(8) (B) f(10) (C) f(12) (D) f(18) (E) f(28)
Solution :
f(4) = 2(4) + 4 ==> 8 + 4 ==> 12
f(6) = 2(6) + 4 ==> 12 + 4 ==> 16
f(4) + f(6) = 12 + 16
f(4) + f(6) = 28
f(12) = 2(12) + 4
f(12) = 24 + 4
f(12) = 28
Problem 6 :
z(q) = 4q + 1/2
The zoomster function z used in space flight engineering is defined above. If, for some number u, z(u + 1/2) = 1/2, then what is the value of u ?
(A) −3/2 (B) −1/2 (C) −1/8 (D) 1/8 (E) 1/2
Solution :
Given :
z(q) = 4q + 1/2
z(u + 1/2) = 1/2
4(u + 1/2) + 1/2 = 1/2
4(u + 1 /2) = 0
u + 1/2 = 0
u = -1/2
Problem 7 :
For the function f graphed in the xy plane above, if f(−2.5) = k, then what is f(2k) ?
Solution :
f(−2.5) = k
By observing the graph, f(−2.5) = 1
So, k = 1, then 2k = 2
f(2) = 0
Problem 8 :
The volume of a balloon is given by the equation
V = t2 - 3t + 3
What is the volume of the balloon after 3 seconds ?
(A) 3 (B) 6 (C) 9 (D) 12
Solution :
V = t2 - 3t + 3
V - Volume, t - time in seconds
t = 3
V = 32 - 3(3) + 3
V = 9 - 9 + 3
V = 3
Problem 9 :
In the table above, if y = x2 + x - 2, what is the value of k ?
Solution :
y = x2 + x - 2
When x = 1, then y = 0
if x = 2, then y = h
h = 22 + 2 - 2
h = 4
When x = 4, y = k
k = 42 + 4 - 2
k = 16 + 4 - 2
k = 20 - 2
k = 18
Problem 10 :
The distance d, in meters, traveled by a rocket depends on the amount of fuel f, in liters, it burns according to the equation d = (2/3)f . Based on the table above, how many rockets traveled more than 20 meters ?
(A) one (B) Two (C) Three (D) Four
Solution :
d = (2/3)f
Number of rockets traveled more than 20 meters = 4
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM