EVALUATE THE LIMIT BY DIRECT SUBSTITUTION
Evaluate the following limits
Problem 1 :
Solution :
= limx→5 10 - x2Applying the given limit, we get= 10 - 52= 10 - 25= -15
Problem 2 :
limx→-2 12x3-5x
Solution :
= limx→-2 12x3-5xApplying the given limit, we get=12(-2)3-5(-2)=12(-8)+10= -4+10= 6
Problem 3 :
limx→-3 2x2+4x+1
Solution :
= limx→-3 2x2+4x+1Applying the limit, we get= 2(-3)2+4(-3)+1= 2(9)-12+1= 18-12+1= 19-12= 7
Problem 4 :
limx→-2 x3-6x+5
Solution :
= limx→-2 x3-6x+5Applying the limit, we get= (-2)3-6(-2)+5= -8+12+5= -8+17= 9
Problem 5 :
limx→3 -9x
Solution :
= limx→3 -9xApplying the limit, we get= -93= -3
Problem 6 :
limx→-5 6x+2
Solution :
= limx→-5 6x+2Applying the limit, we get= 6-5+2=6-3= -2
Problem 7 :
limx→-3 3xx2+1
Solution :
= limx→-3 3xx2+1Applying the limit, we get= 3(-3)(-3)2+1=-99+1= -910
Problem 8 :
limx→4 x-1x2+2x+3
Solution :
lim x→4 x-1x2+2x+3Applying the given limit, we get= 4-142+2(4)+3= 316+8+3= 327= 19
Problem 9 :
limx→-2 5x+32x-9
Solution :
= limx→-2 5x+32x-9Applying the limit, we get= 5(-2)+32(-2)-9=-10+3-4-9= -7-13= 713
Problem 10 :
limx→3 x2+1x
Solution :
= limx→3 x2+1xApplying the limit, we get= 32+13=9+13= 103