Problem 1 :
Domain of the function sin-1 x is ....
Solution:
Consider the given function as,
y = sin-1 x
The graph of sin-1 x or arc sin x is given as
-π/2 ≤ sin-1x ≤ π/2
-1 ≤ sin-1x ≤ 1
Hence, the domain of the function is [-1, 1].
Problem 2 :
Range of the function cos-1x is ....
Solution:
Range of the function cos-1x is [0, π].
Problem 3 :
The principal value of tan-1√3 is .....
Solution:
Let y = tan-1(√3)
tan y = √3
We know that the range of the principal value branch of tan-1(-π/2, π/2).
tan y = tan(π/3)
y = π/3
Hence, the principal value of tan-1(√3) is π/3.
Problem 4 :
Solution:
Problem 5 :
Principal values of the function tan-1x lie in the interval....
Solution:
We know that range of principal value of tan-1x is (-π/2, π/2).
Problem 6 :
Solution:
Problem 7 :
Solution:
Problem 8 :
Solution:
Problem 9 :
Solution:
Domain of sec-1(1/2) is R - (-1, 1).
(i.e) (-∞, -1] ∪ [1, ∞)
So, no set of values exist for sec-1(1/2).
Therefore, ∅ is the answer.
Problem 10 :
For x ∈ R, tan-1(x2 + 1) + cot-1(x2 + 1) is equal to ....
Solution:
Problem 11 :
If cos-1(-x) = α - cos-1x, then the value of α is ....
Solution:
We know that cos-1(-x) = π - cos-1x
By comparing, we get α = π
Hence, α = π.
Problem 12 :
Solution:
Given, |x| ≥ √2
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