DERIVATIVE OF RATIONAL FUNCTION WITHOUT USING QUOTIENT RULE
Here we see derivatives of rational functions without using quotient rule.
Problem 1 :
y = 2x + 5 / x
Solution :
Problem 2 :
y = (x³ - 2) / x
Solution :
Problem 3 :
y = (x³ - 2) / x
Solution :
Problem 4 :
y = (x3 - 4x2 + 3x - 2)/x2
Solution :
Problem 5 :
y = (3x7 - 7x + 11)/2x3
Solution :
Problem 6 :
y = (2x + 3)(2x - 3)/x
Solution :
y = ((2x)2 - 32)/x
y = (4x2 - 9)/x
y = 4x2-9xy = 4x2x9xy = 4x-9x-1= 4(1)-9(-1)x-1-1= 4+9x-2= 4+9x2
Problem 7 :
y = (x + 6)/x3
Solution :
y =x+6x3y = xx3+6x3y =1x2+6x3y =x-2+6x-3 dydx= -2x-2-1+6(-3)x-3-1dydx= -2x3-18x4
Problem 8 :
y = (2x3 + x + 4)/2x5
Solution :
y =2x3+x+42x5y = 2x32x5+x2x542x5y =1x2+12x52x5y =x-2+12x-5+2x-5 dydx= -2x-2-1+12(-5)x-5-1+2(-5)x-5-1dydx= -2x-3-52x-6-10x-6dydx= -2x3-52x6-10x6
Problem 9 :
y = (x - 3)/√x
Solution :
y =x-3xy = xx-3xy = xx-1/2- 3x-1/2y = x1/2- 3x-1/2dydx =12 x1/2 - 1 - 3-12x-1/2-1dydx =12 x-1/2 + 32x-3/2dydx =12x + 32xx