Complete each table of values for the given values of x.
Problem 1 :
y = x + 3
Solution :
put x = -1 y = -1 + 3 y = 2 |
put x = 0 y = 0 + 3 y = 3 |
put x = 1 y = 1 + 3 y = 4 |
put x = 2 y = 2 + 3 y = 5 |
put x = 3 y = 3 + 3 y = 6 |
So, the values of y is 2, 3, 4, 5 and 6.
Problem 2 :
y = 3
Solution :
x = -1 y = 3 |
x = 0 y = 3 |
x = 1 y = 3 |
x = 2 y = 3 |
x = 3 y = 3 |
Problem 3 :
y = (1/2)x - 1
Solution :
put x = -1 y = (1/2) × -1 – 1 = (-1/2) – 1 = (-1 – 2)/2 = -3/2 |
put x = 0 y = (1/2) × 0 – 1 = -1 |
put x = 1 y = (1/2) × 1 – 1 = 1/2 – 1 = (1 – 2)/2 = -1/2 |
put x = 2 y = (1/2) × 2 – 1 = 2/2 – 1 = (2 – 2)/2 = 0 |
put x = 3 y = (1/2) × 3 – 1 = 3/2 – 1 = (3 – 2)/2 = 1/2 |
So, the values of y is -3/2, -1, -1/2, 0 and 1/2.
Problem 4 :
y = 2x - 4
Solution :
y = 2x - 4
put x = -1 y = 2(-1) – 4 = -2 – 4 = -6 |
put x = 0 y = 2(0) – 4 = 0 – 4 = -4 |
put x = 1 y = 2(1) – 4 = 2 – 4 = -2 |
put x = 2 y = 2(2) – 4 = 4 – 4 = 0 |
put x = 3 y = 2(3) – 4 = 6 – 4 = 2 |
So, the values of y is -6, -4, -2, 0 and 2.
Problem 5 :
y = (-1/2)x
Solution :
y = (-1/2)x
put x = -1 y = (-1/2) × -1 = 1/2 |
put x = 0 y = (-1/2) × 0 = 0 |
put x = 1 y = (-1/2) × 1 = -1/2 |
put x = 1 y = (-1/2) × 1 = -1/2 |
put x = 2 y = (-1/2) × 2 = -2/2 = -1 |
put x = 3 y = (-1/2) × 3 = -3/2 |
So, the values of y is1/2, 0, -1/2, -1 and -3/2.
Problem 6 :
y = -2x + 1
Solution :
y = -2x + 1
put x = -1 y = -2(-1) + 1 = 2 + 1 = 3 |
put x = 0 y = -2(0) + 1 = 0 + 1 = 1 |
put x = 1 y = -2(1) + 1 = -2 + 1 = -1 |
put x = 2 y = -2(2) + 1 = -4 + 1 = -3 |
put x = 3 y = -2(3) + 1 = -6 + 1 = -5 |
So, the values of y is 3, 1, -1, -3 and -5.
Problem 7 :
y = x - 1
Solution :
y = x - 1
put x = -1 y = -1 – 1 y = -2 |
put x = 0 y = 0 – 1 y = -1 |
put x = 1 y = 1 – 1 y = 0 |
put x = 2 y = 2 – 1 y = 1 |
put x = 3 y = 3 – 1 y = 2 |
So, the values of y is -2, -1, 0, 1 and 2.
Problem 8 :
2x – y = 4
Solution :
2x – y = 4
put x = -1 2(-1) – y = 4 -2 – y = 4 -y = 4 + 2 y = -6 |
put x = 0 2(0) – y = 4 -y = 4 y = -4 |
put x = 1 2(1) – y = 4 2 – y = 4 -y = 4 – 2 y = -2 |
put x = 2 2(2) – y = 4 4 – y = 4 -y = 4 – 4 y = 0 |
put x = 3 2(3) – y = 4 6 – y = 4 -y = 4 – 6 y = 2 |
So, the values of y is -6, -4, -2, 0 and 2.
Problem 9 :
x = 7
Solution :
x = 7
For all values of y, we will get x as 7.
So, the points are (7, -1), (7, 0) (7, 1) (7, 2) and (7, 3).
Problem 10 :
x + y = -1
Solution :
x + y = -1
put x = -1 -1 + y = -1 y = -1 + 1 y = 0 |
put x = 0 0 + y = -1 y = -1 - 0 y = -1 |
put x = 1 1 + y = -1 y = -1 - 1 y = -2 |
put x = 2 2 + y = -1 y = -1 - 2 y = -3 |
put x = 3 3 + y = -1 y = -1 - 3 y = -4 |
So, the values of y is 0, -1, -2, -3 and -4.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
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