Determine if d(x) is a factor of f(x).
Problem 1 :
f(x) = x3 + 3x2 - 6x - 18
d(x) = x + 3
Solution :
To check if d(x) is a factor of the given polynomial f(x).
x + 3 = 0
x = -3
f(-3) = (-3)3 + 3(-3)2 - 6(-3) - 18
f(-3) = -27 + 27 + 18 - 18
f(-3) = 0
Since the remainder is 0, d(x) is the factor of the polynomial f(x).
Determine if d(x) is a factor of f(x).
Problem 2 :
f(x) = 3x4 + 7x3 + 3x2 - x – 4
d(x) = x + 2
Solution :
x + 2 = 0
x = -2
f(-2) = 3(-2)4 + 7(-2)3 + 3(-2)2 – (-2) – 4
= 48 - 56 + 12 + 2 - 4
= 2
Since the remainder is not equal to zero, we can decide x + 2 is not a factor of the given polynomial f(x).
Problem 3 :
f(x) = 2x3 – x2 - 6x - 1
d(x) = x + 1
Solution :
x + 1 = 0
x = -1
f(-1) = 2(-1)3 – (-1)2 – 6(-1) - 1
= -2 - 1 + 6 - 1
= 2
Since the remainder is not equal to zero, we can decide x + 1 is not a factor of the given polynomial f(x).
Problem 4 :
f(x) = 4x3 - 2x2 + x - 3
d(x) = x - 1
Solution :
x - 1 = 0
x = 1
f(1) = 4(1)3 – 2(1)2 + 1 - 3
= 4 - 2 + 1 - 3
= 0
Since the remainder is equal to zero, we can decide x - 1 is a factor of the given polynomial f(x).
Problem 5 :
f(x) = 3x4 - 3x3 - 9x2 + 5x – 2
d(x) = x - 2
Solution :
x - 2 = 0
x = 2
f(2) = 3(2)4 – 3(2)3 – 9(2)2 + 5(2) – 2
= 48 - 24 - 36 + 10 - 2
= -4
Since the remainder is not equal to zero, we can decide x – 2 is not a factor of the given polynomial f(x).
Problem 6 :
If x – 1 is a factor of the polynomial
p(x) = ax2 – 3(a – 1)x – 1, then find the value of ‘a’?
Solution :
Given, x – 1 is a factor of the polynomial
x – 1 = 0
x = 1
p(x) = ax2 – 3(a – 1)x – 1
p(1) = ax2 – 3ax + 3x – 1
= a(1)2 – 3a(1) + 3(1) – 1
= a – 3a + 3 – 1
= -2a + 2
-2a = -2
Dividing -2 on both sides.
-2/-2a = -2/-2
a = 1
Hence, the value of a is 1.
Problem 7 :
Check If x + 1 is a factor of polynomial, hence evaluate p(-1).
p(x) = 6x3 + 5x2 - 3x + 2,
Solution :
Given, x + 1 is a factor of polynomial
x + 1 = 0
x = -1
p(-1) = 6(-1)3 + 5(-1)2 – 3(-1) + 2,
= -6 + 5 + 3 + 2
p (-1) = 4
Hence, the value of p(-1) is 4.
Problem 8 :
For what value of m is x3 – 2mx2 + 16 divisible by x + 2
Solution :
Let p(x) = x3 – 2mx2 + 16
P(x) is divisible by x + 2.
x + 2 = 0
x = -2
p(-2) = x3 – 2mx2 + 16
= (-2)3 – 2m(-2)2 + 16
= -8 – 2m(4) + 16
= -8 – 8m + 16
= 8 – 8m
8m = 8
Dividing 8 on both sides.
8m/8 = 8/8
m = 1
So, the value of m is 1.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM