For each of the following cubic equations one root is given. Determine the other roots of each cubic.
Problem 1 :
x3 + 3x2 – 6x – 8 = 0 has a root at x = 2.
Problem 2 :
x3 + 2x2 – 21x + 18 = 0 has a root at x = 3.
Problem 3 :
x3 + 4x2 + 7x + 6 = 0 has a root at x = -2.
Problem 4 :
2x3 + 9x2 + 3x – 4 = 0 has a root at x = -4.
For each of the following cubic equations use synthetic division to determine if the given value of x is a root of the equation. Where it is, determine the other roots of the equation.
Problem 5 :
Is x = -2 a root of the equation x3 + 9x2 + 26x + 24 = 0 ?
Problem 6 :
Is x = 4 a root of the equation x3 - 6x2 + 9x + 1 = 0 ?
Problem 7 :
Is x = -1 a root of the equation x3 + 6x2 + 3x - 5 = 0 ?
Problem 8 :
Is x = 2 a root of the equation x3 + 2x2 - 20x + 24 = 0 ?
1) Other root are x = -1, -4 and 2.
2) Other roots are x = -6, 1 and 3.
3) Other roots are x = 3, -1 and -2.
4) Other roots are x = 1/2, -1 and -4.
5) Other roots are x = -3, -4 and -2.
6) x = 4 is not a root.
7) x = -1 is not a root.
8) Roots are x = 2, -6 and 2.
Use the remainder theorem to find f(k).
Problem 1 :
k = 2; f(x) = x² - 2x + 5
A) -5 B) -3 C) -13 D) 5
Problem 2 :
k = -3; f(x) = x² + 2x + 2
A) 1 B) -13 C) 5 D) -17
Problem 3 :
k = -2; f(x) = 3x³ - 7x² - 3x + 3
A) 14 B) -55 C) -43 D) -5
Problem 4 :
k = 4; f(x) = x³ - 2x² + 5x - 2
A) 54 B) 50 C) -78 D) -76
Problem 5 :
k = 2; f(x) = 9x4 + 10x³ + 6x² - 6x + 16
A) 360 B) 500 C) 252 D) 36
Problem 6 :
k = 5; f(x) = x³ - 3x² - 4x - 5
A) 35 B) 25 C) -225 D) -220
Problem 7 :
Using the remainder theorem find the remainders obtained when x3 + (kx + 8)x + k is divided by x + 1 and x - 2. Hence, find k if the sum of the two remainders is 1.
1) Remainder = 5
2) Remainder = 5
3) Remainder = -43
4) Remainder = 50
5) Remainder = 252
6) Remainder = 25
7) k = -2
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM